Question

Даю 25 баллов.Приготовили раствор сульфата магния массой 98г. с массовой долей соли 7%. Рассчитайте массу вещества и массу воды, необходимые для приготовления данного раствора. Ответ округлите до десятых. С решением через дано,заранее спасибо :3

Answer 1

Объяснение:

дано:

w=7%=0.07

m раствора=98г

найти

m воды

m растворенного вещества

решение:

w=m вещества/m раствора

0.07=m вещества/98

m=0.07*98=6.86г

m воды= m раствора-m вещества

m=98-6.86=91.14г

Answer 2

Calculation of the Mass of Substance and Water for the Solution

To calculate the mass of substance and water required to prepare the given solution, we need to use the information provided: the mass of magnesium sulfate is 98g and the mass fraction of the salt is 7%.

Let's start by calculating the mass of the salt in the solution. The mass fraction of the salt is given as 7%, which means that 7% of the total mass of the solution is magnesium sulfate.

To find the mass of the salt, we can use the following formula:

Mass of Salt = Mass of Solution x Mass Fraction of Salt

Substituting the given values:

Mass of Salt = 98g x 0.07 = 6.86g

Next, we can calculate the mass of water in the solution. Since the mass of the salt is 6.86g, the remaining mass of the solution must be water.

To find the mass of water, we can use the following formula:

Mass of Water = Mass of Solution - Mass of Salt

Substituting the given values:

Mass of Water = 98g - 6.86g = 91.14g

Therefore, the mass of substance required to prepare the solution is approximately 6.86g and the mass of water required is approximately 91.14g.

Please note that the answer has been rounded to the nearest tenth as requested.

I hope this helps! Let me know if you have any further questions.