Question

Розрахуйте відносну молекулярну масу для таких сполук: 1. Сг(ОН) з , Al 2 (S0 4 ) 3 2. Ca(N0 3 ) 2 , Mg 3 (P0 4 ) 2 . 3. А1(ОН) 3 , Ва 3 (Р0 4 ) 2 . 4. PbO, KCl, BaSО 4 , AgNО 3 .

Answer 1

Объяснение:

мяу......................

Answer 2

1. Сg(ОН)3: Atomic mass of Cg = 112.41 g/mol Atomic mass of O = 16.00 g/mol Atomic mass of H = 1.01 g/mol Relative molecular mass = (112.41 g/mol) + 3(16.00 g/mol) + (1.01 g/mol) = 252.44 g/mol

2. Al2(SO4)3: Atomic mass of Al = 26.98 g/mol Atomic mass of S = 32.07 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 2(26.98 g/mol) + 3(32.07 g/mol) + 12(16.00 g/mol) = 342.14 g/mol

3. Ca(NO3)2: Atomic mass of Ca = 40.08 g/mol Atomic mass of N = 14.01 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 40.08 g/mol + 2(14.01 g/mol) + 6(16.00 g/mol) = 164.09 g/mol

4. Mg3(PO4)2: Atomic mass of Mg = 24.31 g/mol Atomic mass of P = 30.97 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 3(24.31 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 262.85 g/mol

5. Al(OH)3: Atomic mass of Al = 26.98 g/mol Atomic mass of O = 16.00 g/mol Atomic mass of H = 1.01 g/mol Relative molecular mass = 26.98 g/mol + 3(16.00 g/mol) + 3(1.01 g/mol) = 78.00 g/mol

6. Ba3(PO4)2: Atomic mass of Ba = 137.33 g/mol Atomic mass of P = 30.97 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 3(137.33 g/mol) + 2(30.97 g/mol) + 8(16.00 g/mol) = 601.92 g/mol

7. PbO: Atomic mass of Pb = 207.2 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 207.2 g/mol + 16.00 g/mol = 223.20 g/mol

8. KCl: Atomic mass of K = 39.10 g/mol Atomic mass of Cl = 35.45 g/mol Relative molecular mass = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol

9. BaSO4: Atomic mass of Ba = 137.33 g/mol Atomic mass of S = 32.07 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 137.33 g/mol + 32.07 g/mol + 4(16.00 g/mol) = 233.39 g/mol

10. AgNO3: Atomic mass of Ag = 107.87 g/mol Atomic mass of N = 14.01 g/mol Atomic mass of O = 16.00 g/mol Relative molecular mass = 107.87 g/mol + 14.01 g/mol + 3(16.00 g/mol) = 169.87 g/mol