Question

при взаимодействии магния с избытком раствора серной кислоты выделился водород объемом 56 дм кубических Вычислите массу прореагировавшего магния и число молекул кислоты вступившей в реакцию​

Answer 1

Ответ:

Дано

М(Mg) = 24 г/моль

V(H₂) = 56 дм³

н. у.

m(Mg) - ?

N(H₂SO₄)- ?

Mg + H₂SO₄ -->MgSO₄ +  H₂↑

ν(H₂) = V(H₂)/Vμ

ν(H₂) = 56/22.4 = 2.5 моль

ν(H₂) =ν(Mg)=ν(H₂SO₄)

ν(Mg) = m(Mg)/М(Mg)

m(Mg) = ν(Mg)* М(Mg)

m(Mg) = 2.5*24=60 г

ν(H₂SO₄) = N/Na

N = ν(H₂SO₄)*Na

N = 2.5 *6.02*10²³=1505*10²¹

Объяснение:

Answer 2

Calculation of the Mass of Reacted Magnesium and the Number of Molecules of Sulfuric Acid

To calculate the mass of the reacted magnesium and the number of molecules of sulfuric acid, we need to use the ideal gas law and stoichiometry.

The balanced chemical equation for the reaction between magnesium and sulfuric acid is:

Mg + H2SO4 → MgSO4 + H2

From the given information, we know that the volume of hydrogen gas produced is 56 dm³.

To calculate the mass of the reacted magnesium, we can use the molar volume of an ideal gas at standard temperature and pressure (STP), which is 22.4 dm³/mol.

Using the molar ratio from the balanced equation, we can determine the number of moles of magnesium that reacted.

The molar ratio between magnesium and hydrogen gas is 1:1. Therefore, the number of moles of magnesium is equal to the number of moles of hydrogen gas.

To calculate the number of moles of hydrogen gas, we can use the ideal gas law:

PV = nRT

Where: P = pressure (assumed to be at STP, so 1 atm) V = volume of gas (56 dm³) n = number of moles R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (assumed to be at STP, so 273 K)

Rearranging the equation to solve for n, we have:

n = PV / RT

Substituting the given values, we get:

n = (1 atm) * (56 dm³) / (0.0821 L·atm/(mol·K) * 273 K)

Calculating this, we find that the number of moles of hydrogen gas is approximately 2.2 moles.

Since the molar ratio between magnesium and hydrogen gas is 1:1, the number of moles of magnesium is also 2.2 moles.

To calculate the mass of the reacted magnesium, we need to know the molar mass of magnesium, which is approximately 24.31 g/mol.

Therefore, the mass of the reacted magnesium can be calculated as:

mass of magnesium = number of moles of magnesium * molar mass of magnesium

Substituting the values, we get:

mass of magnesium = 2.2 moles * 24.31 g/mol

Calculating this, we find that the mass of the reacted magnesium is approximately 53.48 g.

To calculate the number of molecules of sulfuric acid that reacted, we need to know the Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

The molar ratio between sulfuric acid and magnesium is 1:1. Therefore, the number of molecules of sulfuric acid is equal to the number of moles of magnesium.

Therefore, the number of molecules of sulfuric acid that reacted is approximately 2.2 x 6.022 x 10^23 molecules.

Please note that the calculations provided are based on the given information and assumptions.