Question

Скласти молекулярні та іонні рівняння реакцій NA3PO4 та CACl2 K2CO3 та BaCl2 Zn(OH)2 та KOH

Answer 1

Ответ:

Объяснение:

2Na3PO4 + 3CaCl2 = Ca3(PO4)2↓ + 6NaCl

6Na(+) + 2PO4(3-) +3Ca(2+) + 6Cl(-) = Ca3(PO4)2↓ + 6Na(+) + 6Cl(-)

3Ca(2+) + 2PO4(3-) = Ca3(PO4)2↓

K2CO3 + BaCl2 = BaCO3↓ + 2KCl

2K(+) + CO3(2-) + Ba(2+) + 2Cl(-) = BaCO3↓ + 2K(+) + 2Cl(-)

Ba(2+) + CO3(2-) = BaCO3↓

Zn(OH)2 + 2KOH = K2[Zn(OH)4]

Zn(OH)2 + 2K(+) + 2OH(-) = 2K(+) + [Zn(OH)4] (2-)

Zn(OH)2 + 2OH(-) = [Zn(OH)4](2-)

Answer 2

Molecular and Ionic Equations for the Reactions

To determine the molecular and ionic equations for the given reactions, let's break down each compound into its constituent ions and then balance the equations.

1. Reaction between Na3PO4 and CaCl2:

The molecular equation is: Na3PO4 + CaCl2 -> ?

Breaking down the compounds into ions: Na3PO4 -> 3Na+ + PO4^3- CaCl2 -> Ca^2+ + 2Cl-

The balanced ionic equation is: 3Na+ + PO4^3- + Ca^2+ + 2Cl- -> ?

2. Reaction between K2CO3 and BaCl2:

The molecular equation is: K2CO3 + BaCl2 -> ?

Breaking down the compounds into ions: K2CO3 -> 2K+ + CO3^2- BaCl2 -> Ba^2+ + 2Cl-

The balanced ionic equation is: 2K+ + CO3^2- + Ba^2+ + 2Cl- -> ?

3. Reaction between Zn(OH)2 and KOH:

The molecular equation is: Zn(OH)2 + KOH -> ?

Breaking down the compounds into ions: Zn(OH)2 -> Zn^2+ + 2OH- KOH -> K+ + OH-

The balanced ionic equation is: Zn^2+ + 2OH- + K+ + OH- -> ?

Balancing the Equations

To balance the equations, we need to ensure that the number of each type of atom is the same on both sides of the equation.

1. Reaction between Na3PO4 and CaCl2:

The balanced ionic equation is: 3Na+ + PO4^3- + Ca^2+ + 2Cl- -> 3Na+ + 2Cl- + Ca3(PO4)2

The molecular equation is: Na3PO4 + 3CaCl2 -> 3NaCl + Ca3(PO4)2

2. Reaction between K2CO3 and BaCl2:

The balanced ionic equation is: 2K+ + CO3^2- + Ba^2+ + 2Cl- -> 2K+ + 2Cl- + BaCO3

The molecular equation is: K2CO3 + BaCl2 -> 2KCl + BaCO3

3. Reaction between Zn(OH)2 and KOH:

The balanced ionic equation is: Zn^2+ + 2OH- + K+ + OH- -> Zn(OH)2 + K+

The molecular equation is: Zn(OH)2 + 2KOH -> 2KOH + Zn(OH)2

Summary

The molecular and ionic equations for the given reactions are as follows:

1. Reaction between Na3PO4 and CaCl2: Molecular equation: Na3PO4 + 3CaCl2 -> 3NaCl + Ca3(PO4)2 Ionic equation: 3Na+ + PO4^3- + Ca^2+ + 2Cl- -> 3Na+ + 2Cl- + Ca3(PO4)2

2. Reaction between K2CO3 and BaCl2: Molecular equation: K2CO3 + BaCl2 -> 2KCl + BaCO3 Ionic equation: 2K+ + CO3^2- + Ba^2+ + 2Cl- -> 2K+ + 2Cl- + BaCO3

3. Reaction between Zn(OH)2 and KOH: Molecular equation: Zn(OH)2 + 2KOH -> 2KOH + Zn(OH)2 Ionic equation: Zn^2+ + 2OH- + K+ + OH- -> Zn(OH)2 + K+

Please let me know if you need any further clarification or have any other questions!