Question

ПОМОГИТЕ ПОЖАЛУЙСТА ДАМ 20 БАЛЛО Электролиз Напишите и уравняйте реакции электролиза растворов следующих веществ. Al2 (S04) 3, Na3P04, НС103, Hg (N03) 2​

Answer 1

Объяснение:

Na3PO4 = 3Na(+) + PO4(3-) диссоциация

На катоде: 2H2O + 2e = H2 + 2OH(-)

На аноде: 2H2O - 4e = 4H(+) + O2

Na3PO4 + 5H2O (электролиз) = 2H2 + O2 + 3NaOH + H3PO4

FeCl2 = Fe(2+) + 2Cl(-) диссоциация

На катоде: 2H2O + 2e = H2 + 2OH(-)

На аноде: 2Cl(-) - 2e = Cl2

FeCl2 + 2H2O = H2 + Cl2 + Fe(OH)2

Answer 2

Electrolysis Reactions and Equations

Electrolysis is a process that involves the decomposition of a compound using an electric current. During electrolysis, positive ions migrate towards the negative electrode (cathode), where they gain electrons and are reduced, while negative ions migrate towards the positive electrode (anode), where they lose electrons and are oxidized.

Let's write and balance the electrolysis reactions for the given substances:

1. Al2(SO4)3 (aluminum sulfate): - At the cathode (reduction): Aluminum ions (Al^3+) gain electrons to form aluminum metal (Al): ``` Al^3+ + 3e^- -> Al ``` - At the anode (oxidation): Oxygen ions (O^2-) lose electrons to form oxygen gas (O2): ``` 6O^2- -> 3O2 + 12e^- ```

2. Na3PO4 (sodium phosphate): - At the cathode (reduction): Sodium ions (Na^+) gain electrons to form sodium metal (Na): ``` 3Na^+ + 3e^- -> 3Na ``` - At the anode (oxidation): Phosphate ions (PO4^3-) lose electrons to form oxygen gas (O2) and phosphate radicals (PO3): ``` 2PO4^3- -> O2 + 4PO3 + 12e^- ```

3. HClO3 (chloric acid): - At the cathode (reduction): Hydrogen ions (H^+) gain electrons to form hydrogen gas (H2): ``` 2H^+ + 2e^- -> H2 ``` - At the anode (oxidation): Chlorine ions (Cl^-) lose electrons to form chlorine gas (Cl2): ``` 2Cl^- -> Cl2 + 2e^- ```

4. Hg(NO3)2 (mercury(II) nitrate): - At the cathode (reduction): Mercury(II) ions (Hg^2+) gain electrons to form mercury metal (Hg): ``` Hg^2+ + 2e^- -> Hg ``` - At the anode (oxidation): Nitrate ions (NO3^-) lose electrons to form oxygen gas (O2) and nitrogen dioxide gas (NO2): ``` 2NO3^- -> O2 + 2NO2 + 4e^- ```

Please note that the above reactions are simplified and do not take into account the presence of water or other factors that may affect the electrolysis process.

I hope this helps! Let me know if you have any further questions.