Question

Расставить коэффициенты, посчитать их сумму в реакциях между: 1) оксидом углерода (IV) и оксидом кальция с образованием карбоната кальция, 2) оксидом бария и азотной кислотой с образованием нитрата бария и воды.

Answer 1

Нет конечно, с оксидом алюминия идет реакция обмена

Al2O3 + 6 HNO3 ==> 2Al(NO3)3 + 3 H2O

2HNO3+Ba(OH)2 ==> Ba(NO3)2 + 2H2O

2HNO3+ Na2CO3 ==> CO2 + H2O + NaNO3

Answer 2

#### Reaction 1: Oxide of Carbon (IV) and Oxide of Calcium to form Calcium Carbonate To calculate the coefficients and sum them in the reaction between the oxide of carbon (IV) and the oxide of calcium with the formation of calcium carbonate, we need to balance the equation. The balanced equation for this reaction is: **CO2 + CaO -> CaCO3** Let's assign coefficients to balance the equation: **CO2 + CaO -> CaCO3** **1CO2 + 1CaO -> 1CaCO3** Therefore, the coefficients for this reaction are: **CO2 + CaO -> CaCO3** **1CO2 + 1CaO -> 1CaCO3** The sum of the coefficients is 1 + 1 = 2. #### Reaction 2: Oxide of Barium and Nitric Acid to form Barium Nitrate and Water To calculate the coefficients and sum them in the reaction between the oxide of barium and nitric acid with the formation of barium nitrate and water, we need to balance the equation. The balanced equation for this reaction is: **BaO + 2HNO3 -> Ba(NO3)2 + H2O** Let's assign coefficients to balance the equation: **BaO + 2HNO3 -> Ba(NO3)2 + H2O** **1BaO + 2HNO3 -> 1Ba(NO3)2 + 1H2O** Therefore, the coefficients for this reaction are: **BaO + 2HNO3 -> Ba(NO3)2 + H2O** **1BaO + 2HNO3 -> 1Ba(NO3)2 + 1H2O** The sum of the coefficients is 1 + 2 + 1 + 1 = 5. In summary: 1) The sum of the coefficients in the reaction between the oxide of carbon (IV) and the oxide of calcium with the formation of calcium carbonate is 2. 2) The sum of the coefficients in the reaction between the oxide of barium and nitric acid with the formation of barium nitrate and water is 5. Please let me know if there's anything else I can help you with!