Question

(Mr) - масса всей молекулы Mr(H2O) = 2*Ar(H)+ Ar(O) = 2*1+16=18MgCl2=Ca(OH2)=Al2O3=H3BO3=CuSo4=​

Answer 1

Решение:

1) Mr(H₂O) = 2Ar(H)+Ar(O) = 2×1+16 = 2+16 = 18

2) Mr(MgCl₂) = Ar(Mg)+2Ar(Cl) = 24+2×35,5 = 24+71 = 95

3) Mr[Ca(OH)₂] = Ar(Ca)+2Ar(O)+2Ar(H) = 40+2×16+2×1 = 40+32+2 = 74

4) Mr(Al₂O₃) = 2Ar(Al)+3Ar(O) = 2×27+3×16 = 54+48 = 102

5) Mr(H₃BO₃) = 3Ar(H)+Ar(B)+3Ar(O) = 3×1+11+3×16 = 3+11+48 = 62

6) Mr(CuSO₄) = Ar(Cu)+Ar(S)+4Ar(O) = 40+32+4×16 = 40+32+64 = 136

Answer 2

It seems like you're interested in calculating the molar mass (Mr) of various chemical compounds. Molar mass is the mass of one mole of a substance and is expressed in atomic mass units (amu) or grams per mole (g/mol).

Here are the molar masses of the compounds you mentioned:

1. H2O (Water):

   • Mr(H2O) = 2 * Ar(H) + Ar(O)
   • Mr(H2O) = 2 * 1 + 16
   • Mr(H2O) = 2 + 16
   • Mr(H2O) = 18 g/mol

2. MgCl2 (Magnesium Chloride):

   • Mr(MgCl2) = Ar(Mg) + 2 * Ar(Cl)
   • Mr(MgCl2) = 24.31 + 2 * 35.45
   • Mr(MgCl2) = 24.31 + 70.9
   • Mr(MgCl2) = 95.21 g/mol

3. Ca(OH)2 (Calcium Hydroxide):

   • Mr(Ca(OH)2) = Ar(Ca) + 2 * Ar(O) + 2 * Ar(H)
   • Mr(Ca(OH)2) = 40.08 + 2 * 16 + 2 * 1
   • Mr(Ca(OH)2) = 40.08 + 32 + 2
   • Mr(Ca(OH)2) = 74.08 g/mol

4. Al2O3 (Aluminum Oxide):

   • Mr(Al2O3) = 2 * Ar(Al) + 3 * Ar(O)
   • Mr(Al2O3) = 2 * 26.98 + 3 * 16
   • Mr(Al2O3) = 53.96 + 48
   • Mr(Al2O3) = 101.96 g/mol

5. H3BO3 (Boric Acid):

   • Mr(H3BO3) = 3 * Ar(H) + Ar(B) + 3 * Ar(O)
   • Mr(H3BO3) = 3 * 1 + 10.81 + 3 * 16
   • Mr(H3BO3) = 3 + 10.81 + 48
   • Mr(H3BO3) = 61.81 g/mol

6. CuSO4 (Copper(II) Sulfate):

   • Mr(CuSO4) = Ar(Cu) + Ar(S) + 4 * Ar(O)
   • Mr(CuSO4) = 63.55 + 32.07 + 4 * 16
   • Mr(CuSO4) = 63.55 + 32.07 + 64
   • Mr(CuSO4) = 159.62 g/mol

Please note that these molar masses are approximate and can vary slightly depending on the isotopes of the elements and their respective atomic masses. The values provided here are based on common isotopes.