Question

Сколько граммов азота в 1 моле нитрата калия?

Answer 1

KNO3 - формула
K- 1моль
N - 1 моль
O - 3 моль
m(N)= Mn = 14 * 1 = 14г

Answer 2

Mg(OH)2 + 2HNO3 -> Mg(NO3)2 + 2H2O - реакция нейтрализации
Соотношения n(Mg(NO3)2) к n(HNO3) как 1 к 2, знач n(Mg(NO3)2) = 0.5моль.
m(Mg(NO3)2) = (24+2(14+16*3)) * 0,5  = посчитайте и будет вам ответ...

Answer 3

Calculating the Grams of Nitrogen in 1 Mole of Potassium Nitrate

To calculate the grams of nitrogen in 1 mole of potassium nitrate, we can use the molar mass of potassium nitrate and the molar mass of nitrogen.

Step 1: Calculate the Molar Mass of Potassium Nitrate The molar mass of potassium nitrate (KNO3) can be calculated by adding the atomic masses of its constituent elements: potassium (K), nitrogen (N), and oxygen (O).

The atomic mass of potassium (K) is approximately 39.10 g/mol, nitrogen (N) is approximately 14.01 g/mol, and oxygen (O) is approximately 16.00 g/mol.

The molar mass of potassium nitrate (KNO3) can be calculated as follows: - K: 39.10 g/mol - N: 14.01 g/mol - O: 16.00 g/mol (three oxygen atoms in KNO3)

Molar mass of KNO3 = (39.10 g/mol) + 14.01 g/mol + (16.00 g/mol * 3) = 101.10 g/mol

Step 2: Calculate the Grams of Nitrogen in 1 Mole of Potassium Nitrate Now, we can calculate the grams of nitrogen in 1 mole of potassium nitrate using the molar mass of nitrogen.

The molar mass of nitrogen (N) is approximately 14.01 g/mol.

Grams of nitrogen in 1 mole of potassium nitrate = (14.01 g/mol / 101.10 g/mol) * 1000 mg/g = 138.7 mg

Therefore, there are approximately 138.7 milligrams of nitrogen in 1 mole of potassium nitrate.