Question

V(CH4) = 5000л V(O2) - ? CH4 + 2O2 = CO2 + H2O

Answer 1

5000х2:1=2500 вот все просто

Answer 2

The balanced chemical equation for the combustion of methane (CH4) in oxygen (O2) to produce carbon dioxide (CO2) and water (H2O) is:

CH4 + 2O2 → CO2 + 2H2O

From the equation, you can see that one mole of methane (CH4) reacts with two moles of oxygen (O2) to produce one mole of carbon dioxide (CO2) and two moles of water (H2O).

If you have 5000 liters of methane (V(CH4) = 5000 L), you need to determine the volume of oxygen required, V(O2).

The molar volume of gases under standard conditions (STP) is approximately 22.4 liters per mole. Therefore, you can use this information to calculate the volume of oxygen required.

Since the balanced equation shows a 1:2 ratio between CH4 and O2, for every mole of CH4, you need 2 moles of O2.

1 mole of CH4 requires 2 moles of O2, so 5000 liters of CH4 will require:

5000 L * (2 moles of O2 / 1 mole of CH4) = 10000 L of O2

So, you would need 10,000 liters of oxygen (O2) to completely combust 5000 liters of methane (CH4) in the given reaction.