Question

1. CuCl2 + Ca(OH)2 →2. FeSO4 + HCl →

Answer 1

FeSO4+2 HCl=FeCl2(осадок)+H2SO4
CA(OH)2 + CUCL2 = CACL2 + CU(OH)2

Answer 2

Reaction 1: CuCl2 + Ca(OH)2

The reaction between CuCl2 (copper(II) chloride) and Ca(OH)2 (calcium hydroxide) can be represented as follows:

CuCl2 + Ca(OH)2 → Cu(OH)2 + CaCl2

In this reaction, copper(II) chloride reacts with calcium hydroxide to form copper(II) hydroxide and calcium chloride.

Reaction 2: FeSO4 + HCl

The reaction between FeSO4 (iron(II) sulfate) and HCl (hydrochloric acid) can be represented as follows:

FeSO4 + 2HCl → FeCl2 + H2SO4

In this reaction, iron(II) sulfate reacts with hydrochloric acid to form iron(II) chloride and sulfuric acid.

Please note that the reaction you provided, FeSO4 + HCl, does not specify the stoichiometry. The balanced equation assumes a 1:2 ratio between FeSO4 and HCl.

I hope this helps! Let me know if you have any further questions.