Question

Даны вещества: Fe, H3PO4, H2SO4 (р-р), NaOH, FeCl3, H2O2. Используя воду и необходимые вещества только из этого списка, получите в две стадии гидроксид железа(II). Опишите признаки проводимых реакций. Для реакции ионного обмена напишите сокращенное ионное уравнение реакции

Answer 1

Fecl2+h2so4=feso4+2hcl
feso4+naoh=fe(oh)2+na2so4

Answer 2

Obtaining Iron(II) Hydroxide in Two Stages

To obtain iron(II) hydroxide using water and the listed substances in two stages, we can follow the reactions provided in the search results.

Stage 1: 1. Reaction 1: Iron reacts with copper(II) sulfate to form iron(II) sulfate and copper. - Equation: ``` Fe + CuSO4 = FeSO4 + Cu ```

2. Reaction 2: Iron(II) sulfate reacts with sodium hydroxide to form iron(II) hydroxide and sodium sulfate. - Equation: ``` FeSO4 + 2NaOH = Fe(OH)2 + Na2SO4 ```

Stage 2: The formation of iron(II) hydroxide is achieved in two stages as described above. The reactions involve characteristic color changes and the formation of precipitates, indicating the formation of the desired product.

Ionic Exchange Reaction

The ionic exchange reaction involved in the second stage can be represented as follows: - Ionic Equation: ``` Fe2+ + 2OH- = Fe(OH)2 ```

In this reaction, the iron(II) ion (Fe2+) from the iron(II) sulfate reacts with hydroxide ions (OH-) from the sodium hydroxide to form iron(II) hydroxide.

These reactions demonstrate the process of obtaining iron(II) hydroxide using the listed substances in two stages, along with the characteristics and the ionic exchange reaction involved.