Question

NH2CH2COOH +CH3CHO -> ? NH2CH2COOH + Na(OH)2 -> ?

Answer 1

1 не выходит, может там CH3COOH?
NH2CH2COOH + Na(OH)2 ----> NH2CH2COONa+Н2О

Answer 2

The reactions you've mentioned involve the compound ethylamine (NH2CH2COOH) and different reagents. Let's go through each reaction one by one.

1. Reaction of Ethylamine (NH2CH2COOH) with Acetaldehyde (CH3CHO):

The reaction between ethylamine (NH2CH2COOH) and acetaldehyde (CH3CHO) can result in the formation of a Schiff base or an imine. Here's the balanced chemical equation for the reaction:

NH2CH2COOH + CH3CHO → NH=CHCH2COOH

In the reaction above, the amino group (-NH2) from ethylamine reacts with the carbonyl group of acetaldehyde (-CHO) to form a double bond between the nitrogen and carbon, resulting in the formation of a Schiff base.

2. Reaction of Ethylamine (NH2CH2COOH) with Sodium Hydroxide (NaOH):

When ethylamine (NH2CH2COOH) reacts with sodium hydroxide (NaOH), it undergoes a neutralization reaction to form a salt. Here's the balanced chemical equation for this reaction:

NH2CH2COOH + NaOH → NH2CH2COONa + H2O

In this reaction, the amine group (-NH2) in ethylamine reacts with the hydroxide ion (-OH) from sodium hydroxide, resulting in the formation of the salt NH2CH2COONa (sodium ethylate) and water (H2O).

So, in summary:

1. Reaction of Ethylamine (NH2CH2COOH) with Acetaldehyde (CH3CHO) forms a Schiff base NH=CHCH2COOH.

2. Reaction of Ethylamine (NH2CH2COOH) with Sodium Hydroxide (NaOH) forms the salt NH2CH2COONa (sodium ethylate) and water (H2O).