Question

KMno4+kbr+h2so4->k2so4+br2+mnso4+h2o

Answer 1

Ответ:

Объяснение:

KMno4+kbr+h2so4->k2so4+br2+mnso4+h2o

 2KMnO4 +  10KBr   + 8H2SO4 =  6K2SO4  +  5Br2↓  +  2MnSO4  + 8H2O

     Mn⁺⁷ + 5e =  Mn⁺²  восстановление,  KMnO4 - окислитель  ║2

    2Br⁻ - 2e  =  Br₂⁰  окисление, KBr -  восстановитель              ║5

Answer 2

The chemical equation you've provided represents a reaction between potassium permanganate (KMnO4), potassium bromide (KBr), and sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4), bromine (Br2), manganese sulfate (MnSO4), and water (H2O).

Here's the balanced chemical equation for this reaction:

2 KMnO4 + 16 H2SO4 + 10 KBr → 6 K2SO4 + 5 Br2 + 2 MnSO4 + 8 H2O

In this balanced equation:

• 2 moles of KMnO4 react with 10 moles of KBr, 16 moles of H2SO4, and produce 6 moles of K2SO4, 5 moles of Br2, 2 moles of MnSO4, and 8 moles of H2O.

Remember that balancing chemical equations is important to ensure that mass is conserved and the number of atoms of each element on the reactant side equals the number of atoms of the same element on the product side.