Question

При сгорании 3 валентного металла, массой 11.2 грамма образовался оксид, массой 16 грамм. Какой металл был взят? С решением пожалуйста и поподробнее....)

Answer 1

Формула оксида: Ме2О3, тогда соотношение молей элементов: Ме:О=2:3=11,2/М(Ме):(16-11,2)/М(О2)=11,2/М(Ме):4,8/16=11,2/М(Ме):0,3, значит 11,2/М(Ме)=0,3/3*2=0,2, отсюда Ме=11,2/0,2=56 г/моль - железо

Answer 2

Identification of the Problem

The problem states that when a 3-valent metal with a mass of 11.2 grams undergoes combustion, it forms an oxide with a mass of 16 grams. We need to determine the identity of the metal.

Solution

To solve this problem, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions.

In this case, we can set up a stoichiometric equation to relate the mass of the metal and the mass of the oxide formed. The equation can be written as follows:

Metal + Oxygen → Metal Oxide

Let's assume the molar mass of the metal is M grams/mol and the molar mass of the oxide is MO grams/mol.

According to the problem, the mass of the metal is 11.2 grams and the mass of the oxide is 16 grams.

Using the molar masses, we can set up the following equation:

11.2 g (M grams/mol) + Oxygen → 16 g (MO grams/mol)

To find the molar mass of the metal, we need to know the molar mass of the oxide. Unfortunately, the problem does not provide this information. Therefore, we cannot determine the identity of the metal with the given information.

If we had the molar mass of the oxide, we could calculate the molar mass of the metal using the equation above. However, without that information, we cannot proceed further.

Conclusion

In conclusion, based on the information provided in the problem, we cannot determine the identity of the metal. We would need additional information, such as the molar mass of the oxide, to solve the problem.