
ПОМОГИТЕ! получить 5 способами BA3(PO4)2 в молекулярном и ионном виде Получить поваренную соль 3
способами

Ответы на вопрос

1)2H3PO4+3BaO=Ba3(PO4)2+3H2O
2)2BaHPO4 + Ba(OH)2=Ba3(PO4)2+2H2O
3)2H3PO4+3BaSO4=Ba3(PO4)2+3H2SO4



1.Ba3(PO4)
Ba +2H3PO4 =Ba3(PO4)2 +3H2
Ba(0) +6H+ +2PO4(3-)=Ba3(PO4)2 +3H2
3BaO+2H3PO4 =Ba3(PO4)2 +3H2O
3BaO + 6H+ +2PO4(3-) =Ba3(PO4)2 +3H2O
3Ba(OH)2 + 2H3PO4=Ba3(PO4)2 +6H2O
3Ba+2 +6H+ +2PO4-3 +6Cl- =Ba3(PO4)2 +6H+ +6Cl-
3Ba+2 +2PO4 -3 =Ba3(PO4)2
3BaCl2+2 Na3PO4=Ba3(PO4)2 + 6NaCl
3Ba+2 +6Cl- +6Na+ +2PO4-3=Ba3(PO4)2 +6Na+ +6Cl-
3Ba+2 + 2PO4-3=Ba3(PO4)2
2.NaCl
Na2O +2HCl =2NaCl +H2O, Na2O +2H+ +2Cl-=2Na++2Cl- +H2O, Na2O +2H+=2Na+ =H2O
NaOH +HCl=NaCl +H2O
Na+ +OH- +H+ +Cl-=Na+ +Cl- +H2O,H+ +OH-=H2O
3Ba+2 +6OH- +6H+ 2PO4-3 =Ba3(PO4)2 +6H2O
3BaCl2 +2H3PO4 =Ba3(PO4)2 +6HCl



Obtaining BA3(PO4)2 in Molecular and Ionic Forms
To obtain BA3(PO4)2 in molecular and ionic forms, you can use the following methods:
1. Molecular Form: - The molecular formula for BA3(PO4)2 is obtained by combining barium ions (Ba2+) and phosphate ions (PO4^3-). - The molecular form of BA3(PO4)2 can be represented as Ba3(PO4)2.
2. Ionic Form: - The ionic form of BA3(PO4)2 involves the dissociation of the compound into its constituent ions. - In the ionic form, BA3(PO4)2 can be represented as 3Ba^2+ + 2(PO4)^3-.
Obtaining BA3(PO4)2 as a Precipitate
To obtain BA3(PO4)2 as a precipitate, you can use the following methods:
1. Method 1: - One method to obtain BA3(PO4)2 as a precipitate is by reacting barium chloride (BaCl2) with sodium phosphate (Na3PO4) to form a precipitate of BA3(PO4)2. - The balanced chemical equation for this reaction is: 3BaCl2 + 2Na3PO4 → Ba3(PO4)2 + 6NaCl.
2. Method 2: - Another method involves the reaction of barium nitrate (Ba(NO3)2) with ammonium phosphate ((NH4)3PO4) to produce BA3(PO4)2 as a precipitate. - The balanced chemical equation for this reaction is: 3Ba(NO3)2 + 2(NH4)3PO4 → Ba3(PO4)2 + 6NH4NO3.
3. Method 3: - A third method is the reaction of barium hydroxide (Ba(OH)2) with phosphoric acid (H3PO4) to yield BA3(PO4)2 as a precipitate. - The balanced chemical equation for this reaction is: 3Ba(OH)2 + 2H3PO4 → Ba3(PO4)2 + 6H2O.
These methods provide different approaches to obtain BA3(PO4)2 in both molecular and ionic forms, as well as as a precipitate through various chemical reactions.


Топ вопросов за вчера в категории Химия
Последние заданные вопросы в категории Химия
-
Математика
-
Литература
-
Алгебра
-
Русский язык
-
Геометрия
-
Английский язык
-
Химия
-
Физика
-
Биология
-
Другие предметы
-
История
-
Обществознание
-
Окружающий мир
-
География
-
Українська мова
-
Информатика
-
Українська література
-
Қазақ тiлi
-
Экономика
-
Музыка
-
Право
-
Беларуская мова
-
Французский язык
-
Немецкий язык
-
МХК
-
ОБЖ
-
Психология
-
Физкультура и спорт
-
Астрономия
-
Кыргыз тили
-
Оʻzbek tili