Question

CuSO4+NaOH =AlCl3+NaOH=FeSO4+NaOH=​

Answer 1

Ответ:

CuSO4 + 2NaOH —> Cu(OH)2 + Na2SO4

AlCl3 + 3NaOH —> Al(OH)3 + 3NaCl

FeSO4 + 2NaOH —> Fe(OH)2 + Na2SO4

Answer 2

It appears that you've provided a series of chemical reactions involving different compounds and reagents. Let's examine each reaction separately:

1. CuSO4 + NaOH: Copper sulfate (CuSO4) reacts with sodium hydroxide (NaOH) to form copper hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4) as follows:

   CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

2. AlCl3 + NaOH: Aluminum chloride (AlCl3) reacts with sodium hydroxide (NaOH) to form aluminum hydroxide (Al(OH)3) and sodium chloride (NaCl) as follows:

   AlCl3 + 3NaOH → Al(OH)3 + 3NaCl

3. FeSO4 + NaOH: Iron(II) sulfate (FeSO4) reacts with sodium hydroxide (NaOH) to form iron(II) hydroxide (Fe(OH)2) and sodium sulfate (Na2SO4) as follows:

   FeSO4 + 2NaOH → Fe(OH)2 + Na2SO4

It's important to note that in each of these reactions, a double displacement reaction occurs, where the positive ions in one reactant switch places with the positive ions in the other reactant to form new compounds. The products are generally solid precipitates and soluble salts. If you have any specific questions about these reactions or their applications, please feel free to ask.