
Mo O2 + H2 → Mo + H2O


Ответы на вопрос

Восстанавление оксида молибдена(IV) водородом:
MoO2 + 2H2 → Mo + 2H2O



The chemical equation you've provided seems to represent a reaction involving molybdenum (Mo), oxygen (O2), hydrogen (H2), and water (H2O). However, the equation appears to be unbalanced. To balance it, you need to ensure that there are an equal number of each type of atom on both sides of the arrow.
Let's balance the equation step by step:
Mo + O2 + H2 → Mo + H2O
Balance the molybdenum (Mo) atoms first. There's one Mo atom on both sides, so that's already balanced.
Balance the oxygen (O) atoms. On the left side, there are two oxygen atoms in O2, and on the right side, there's only one oxygen atom in H2O. To balance the oxygen atoms, you need to add another O2 molecule to the right side:
Mo + O2 + H2 → Mo + H2O + O2
- Now, let's balance the hydrogen (H) atoms. On the left side, there are two hydrogen atoms in H2, and on the right side, there are two hydrogen atoms in H2O. Hydrogen atoms are already balanced.
The balanced chemical equation is:
Mo + O2 + H2 → Mo + H2O + O2
This equation now shows that the number of each type of atom is the same on both sides of the arrow, which is the requirement for a balanced chemical equation.


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