Question

Дано: V(SO2)=67.2 Найти: m(K2SO3)?

Answer 1

    67,2 л                                              Х г

    SO2         +        K2O        ->           K2SO3

n=1 моль                                         n=1 моль

Vm=22,4 л/моль                              M = 158 г/моль

V = 22,4 л                                        m = 158 г

67,2 л SO2     -     Х г K2SO3

22,4 л SO2     -    158 г K2SO3

m(K2SO3) = 67,2 * 158 / 22,4 = 474 г

Answer 2

67.2л. х
SO2+ K2O---K2SO3
22.4л. 158г


x=67,2×158/22,4=474г

Answer 3

To find the molar mass of K2SO3 (potassium sulfite), we need to use the given information and some periodic table data.

Given: V(SO2) = 67.2 (I assume you meant to write g, which stands for grams)

We want to find the molar mass of K2SO3 (m(K2SO3)).

Steps to calculate molar mass:

Step 1: Write down the chemical formula of K2SO3, which is made up of potassium (K), sulfur (S), and oxygen (O) atoms.

Step 2: Determine the molar mass of each element involved in the compound. You can find the molar masses of each element on the periodic table:

• Molar mass of K (potassium) = 39.10 g/mol
• Molar mass of S (sulfur) = 32.06 g/mol
• Molar mass of O (oxygen) = 16.00 g/mol

Step 3: Calculate the molar mass of K2SO3 by adding up the molar masses of all the atoms in the compound:

m(K2SO3) = 2 * m(K) + 1 * m(S) + 3 * m(O)

Substitute the molar masses: m(K2SO3) = 2 * 39.10 g/mol + 1 * 32.06 g/mol + 3 * 16.00 g/mol

m(K2SO3) = 78.20 g/mol + 32.06 g/mol + 48.00 g/mol

Step 4: Perform the calculations: m(K2SO3) = 158.26 g/mol

The molar mass of K2SO3 (potassium sulfite) is approximately 158.26 g/mol.