Question

M(Cu)=3,2т m(Cu O)-?

Answer 1

2Cu + O2 = 2CuO
64 --- 3.2т
80 --- х= 4т

Answer 2

To find the mass of copper oxide (CuO), we can use the law of conservation of mass, which states that in a chemical reaction, the total mass of the reactants is equal to the total mass of the products.

The chemical reaction involved here is the formation of copper oxide (CuO) from copper (Cu) and oxygen (O) in the air. The balanced chemical equation for this reaction is:

2Cu + O2 → 2CuO

According to the equation, 2 moles of copper (2M(Cu)) react with 1 mole of oxygen (1M(O2)) to form 2 moles of copper oxide (2M(CuO)).

Given that M(Cu) = 3.2 g (mass of copper), we can find the molar mass of copper (Cu) by looking up its atomic mass:

Molar mass of Cu (Cu): 63.55 g/mol

Now, we can set up a proportion to find the molar mass of copper oxide (CuO) from the mass of copper (Cu):

Molar mass of Cu (Cu) / Mass of Cu (Cu) = Molar mass of CuO (CuO) / Mass of CuO (CuO)

63.55 g/mol / 2 moles = Molar mass of CuO (CuO) / 2 moles

Solving for the molar mass of CuO (CuO):

Molar mass of CuO (CuO) = 63.55 g/mol / 2 moles = 31.775 g/mol

Now, we know the molar mass of copper oxide (CuO) is approximately 31.775 g/mol.

Finally, to find the mass of copper oxide (CuO), we need to multiply the number of moles of copper oxide (2 moles) by its molar mass:

Mass of CuO (CuO) = 2 moles * 31.775 g/mol ≈ 63.55 g

So, the mass of copper oxide (CuO) formed is approximately 63.55 grams.