Question

Zn +2HCl = ZnCl2+H2 Zn=40г Найти массу HCl

Answer 1

Ответ масса HCL 44.9 грамм

Answer 2

40 г. Х г
Zn. +. 2HCl. =. ZnCl2. +. H2
n=1 моль. n=2 моль
М=65 г/моль. М=36,5 г/моль
m=65 г. m=73 г
40 г Zn. -. Х г HCl
65 г Zn. -. 73 г HCl
m(HCl)=40*73/65=45 г

Answer 3

To find the mass of HCl required for the given reaction, we can first calculate the stoichiometry of the reaction to determine the molar ratio between Zn and HCl. Then, we can use the molar mass of HCl to find the required mass.

The balanced chemical equation for the reaction is:

Zn + 2HCl -> ZnCl2 + H2

From the equation, we can see that 1 mole of Zn reacts with 2 moles of HCl.

Step 1: Calculate moles of Zn: Given mass of Zn = 40 g Molar mass of Zn (Zinc) = 65.38 g/mol

Number of moles of Zn = Mass of Zn / Molar mass of Zn Number of moles of Zn = 40 g / 65.38 g/mol ≈ 0.612 moles

Step 2: Calculate moles of HCl: Molar ratio between Zn and HCl from the balanced equation is 1:2.

Number of moles of HCl = Number of moles of Zn × (2 moles of HCl / 1 mole of Zn) Number of moles of HCl = 0.612 moles × 2 ≈ 1.224 moles

Step 3: Calculate the mass of HCl: Molar mass of HCl (Hydrochloric acid) = 36.46 g/mol

Mass of HCl = Number of moles of HCl × Molar mass of HCl Mass of HCl = 1.224 moles × 36.46 g/mol ≈ 44.64 g

So, the mass of HCl required for the reaction is approximately 44.64 grams.