Question

M(naoh)=46 г m(H2SO4)равно 98 грамм найти m(Na2SO4)

Answer 1

2NaOH+H2SO4=Na2SO4+2H2O

46 г----------------------х=81,65 г

80 г-----------------------142 г

Answer 2

To find the mass of sodium sulfate (Na2SO4) formed when sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4), we need to balance the chemical equation first to determine the stoichiometry of the reaction.

The balanced chemical equation for the reaction between NaOH and H2SO4 is as follows:

2 NaOH + H2SO4 -> Na2SO4 + 2 H2O

From the balanced equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4 to produce 1 mole of Na2SO4.

Now, let's calculate the number of moles of H2SO4 provided:

m(H2SO4) = 98 grams

Next, we'll convert the mass of H2SO4 to moles using its molar mass. The molar mass of H2SO4 is:

Molar mass of H2SO4 = (2 * Molar mass of H) + Molar mass of S + (4 * Molar mass of O) = (2 * 1.008 g/mol) + 32.06 g/mol + (4 * 16.00 g/mol) = 2.016 g/mol + 32.06 g/mol + 64.00 g/mol = 98.076 g/mol

Now, we can calculate the number of moles of H2SO4:

moles of H2SO4 = m(H2SO4) / Molar mass of H2SO4 = 98 g / 98.076 g/mol ≈ 1 mol

Since 2 moles of NaOH react with 1 mole of H2SO4 to produce 1 mole of Na2SO4, we need to double the number of moles of H2SO4 to find the number of moles of Na2SO4 formed:

moles of Na2SO4 = 2 * moles of H2SO4 = 2 * 1 mol = 2 mol

Finally, let's calculate the mass of Na2SO4:

Molar mass of Na2SO4 = (2 * Molar mass of Na) + Molar mass of S + (4 * Molar mass of O) = (2 * 22.99 g/mol) + 32.06 g/mol + (4 * 16.00 g/mol) = 45.98 g/mol + 32.06 g/mol + 64.00 g/mol = 142.04 g/mol

mass of Na2SO4 = moles of Na2SO4 * Molar mass of Na2SO4 = 2 mol * 142.04 g/mol ≈ 284.08 g

Therefore, the mass of Na2SO4 formed is approximately 284.08 grams.