Question

V(H2O)=50л найти N(H)

Answer 1

Воообще не уверенна. Но как-то так.

Answer 2

To find the number of moles of hydrogen atoms (N(H)) in 50 liters of water (H2O), we need to consider the molar ratio of hydrogen atoms to water molecules.

In one molecule of water (H2O), there are two hydrogen atoms (H). The molar ratio is 2 moles of hydrogen atoms per 1 mole of water.

First, we need to convert the volume of water from liters to moles using the ideal gas law equation:

PV = nRT

Where: P = pressure (assuming it's at standard pressure, which is approximately 1 atm) V = volume of gas in liters n = number of moles of gas R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature in Kelvin

Since we don't have the temperature or pressure information, we'll assume standard temperature (273.15 K) and pressure (1 atm). Therefore, the equation becomes:

(1 atm) * (50 L) = n * (0.0821 L·atm/(mol·K)) * (273.15 K)

50 atm·L = n * 22.414 L·atm/mol

n = 50 atm·L / 22.414 L·atm/mol n ≈ 2.23 moles

Now, since each mole of water (H2O) contains 2 moles of hydrogen (H), we can multiply the number of moles of water by 2 to find the number of moles of hydrogen:

N(H) = 2 * n N(H) ≈ 2 * 2.23 N(H) ≈ 4.46 moles

Therefore, there are approximately 4.46 moles of hydrogen atoms (N(H)) in 50 liters of water (H2O).