Question

M (H₂SO4) - 9,8₂/V (H2) - ?Zn+H₂SO4+H₂​

Answer 1

Ответ:

Объяснение:

                        9,8 г                                  Х л

 Zn       +       H2SO4    =     ZnSO4    +    H2

                    n=1 моль                            n=1 моль

                 М = 98 г/моль                     Vm=22,4 л/моль

                 m=98 г                                  V = 22,4 л

9,8 г  H2SO4    -    Х л   Н2

98 г   H2SO4    -    22,4 л Н2

V(H2) = 9,8 * 22,4 / 98 = 2,24 л

Answer 2

To balance the chemical equation, we need to determine the values of "M," "V," and "Zn" and balance the number of atoms on both sides of the equation. Let's proceed step by step:

1. Write the unbalanced equation:

M (H₂SO₄) + 9,8₂/V (H₂) → ? Zn + H₂SO₄ + H₂

2. Identify the elements and their number of atoms on each side:

Left side: H (2 from H₂SO₄ and V from V(H₂)) Right side: H (2 from H₂SO₄ and 2 from H₂)

3. Balance the hydrogen atoms:

Left side: H: 2 + V Right side: H: 2 + 2 = 4

To balance the hydrogen atoms, we set the equation 2 + V = 4 and solve for V:

V = 4 - 2 V = 2

So, the value of V is 2.

4. Next, let's balance the sulfur atoms:

Left side: Sulfur (1 from H₂SO₄) Right side: Sulfur (1 from H₂SO₄)

The sulfur atoms are already balanced.

5. Finally, let's balance the other element, which is Zinc (Zn):

Left side: Zinc (M) Right side: Zinc (1 from Zn)

To balance Zinc, M must be equal to 1:

M = 1

Now, the balanced chemical equation is:

H₂SO₄ + 9,8₂/V (H₂) → Zn + H₂SO₄ + H₂

Where M = 1, V = 2, and Zn = 1.