Question

CuSO4 (80г) + 2NaOH = Cu(OH)2(m-?) + Na2SO4​

Answer 1

Ответ:n(CuSO4)=80/160=0.5моль

m(Cu(OH)2)=0.5×97=48.5г

Объяснение:

Answer 2

To balance the chemical equation for the reaction between copper sulfate (CuSO4) and sodium hydroxide (NaOH), we need to determine the molar mass of the substances involved and then balance the equation.

1. First, let's find the molar mass of each compound:

• CuSO4 (Copper sulfate): Copper (Cu) has a molar mass of approximately 63.55 g/mol. Sulfur (S) has a molar mass of approximately 32.06 g/mol. Oxygen (O) has a molar mass of approximately 16.00 g/mol. Molar mass of CuSO4 = 63.55 + 32.06 + (16.00 x 4) ≈ 159.61 g/mol.

• NaOH (Sodium hydroxide): Sodium (Na) has a molar mass of approximately 22.99 g/mol. Oxygen (O) has a molar mass of approximately 16.00 g/mol. Hydrogen (H) has a molar mass of approximately 1.01 g/mol. Molar mass of NaOH = 22.99 + 16.00 + 1.01 ≈ 40.00 g/mol.

2. Now, let's balance the chemical equation: CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

To balance the equation, we need to make sure that the same number of atoms of each element is present on both sides of the equation.

• Copper (Cu) is balanced with 1 Cu on both sides.
• Sulfur (S) is balanced with 1 S on both sides.
• Oxygen (O) is balanced with 4 O on both sides.
• Sodium (Na) is balanced with 2 Na on both sides.
• Hydrogen (H) is balanced with 2 H on both sides.

The balanced chemical equation is: CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

Now, we have a balanced equation for the reaction between copper sulfate and sodium hydroxide. However, the mass of Cu(OH)2 (m) formed is not provided in the given information. Without additional information about the reaction conditions and stoichiometry, we cannot calculate the exact mass of Cu(OH)2 formed.