Question

Al->Al2(S04)3->Al(OH)3->Na[Al(OH)4]->Al(N03)3

Answer 1

Ответ:

Объяснение:

2Al + 3H2SO4 = Al2(SO4)3 +3 H2↑

Al2(SO4)3 + 6NaOH = 2Al(OH)3↓ + 3Na2SO4

Al(OH)3 + 2NaOH = Na[Al(OH)4]

Na[Al(OH)4] + 4HNO3 = NaNO3 + Al(NO3)3 + 4H2O

Answer 2

The chemical reactions you have provided describe a series of transformations involving aluminum (Al) and various compounds. Let's break down each step:

1. Al → Al2(SO4)3: This reaction involves the reaction of aluminum with sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3).

2. Al2(SO4)3 → Al(OH)3: In this step, aluminum sulfate reacts with water (H2O) to yield aluminum hydroxide (Al(OH)3) and sulfuric acid.

3. Al(OH)3 → Na[Al(OH)4]: Here, aluminum hydroxide reacts with sodium hydroxide (NaOH) to form sodium tetrahydroxoaluminate, which is commonly written as Na[Al(OH)4].

4. Na[Al(OH)4] → Al(NO3)3: This step involves the reaction of sodium tetrahydroxoaluminate with nitric acid (HNO3) to produce aluminum nitrate (Al(NO3)3) and sodium hydroxide (NaOH).

Overall, these reactions represent a series of transformations where aluminum undergoes chemical reactions to form different compounds such as aluminum sulfate, aluminum hydroxide, sodium tetrahydroxoaluminate, and aluminum nitrate.