
Розстав коефіцієнти в реакції горіння алкану: 2C6H14 + O2 = CO2 + H2O.


Ответы на вопрос




To balance the combustion reaction of an alkane (in this case, hexane, C6H14) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O), you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance the equation:
2 C6H14 + 19 O2 → 12 CO2 + 14 H2O
Explanation:
Balance carbon atoms: There are 6 carbon atoms on each side of the equation, so they are already balanced.
Balance hydrogen atoms: There are 14 hydrogen atoms on the left side (2 moles of C6H14, each containing 7 hydrogen atoms) and 14 hydrogen atoms on the right side (14 moles of H2O, each containing 2 hydrogen atoms).
Balance oxygen atoms: On the left side, there are 19 moles of O2, which means 19 * 2 = 38 oxygen atoms. On the right side, there are 12 moles of CO2, each containing 2 oxygen atoms (12 * 2 = 24 oxygen atoms), and 14 moles of H2O, each containing 1 oxygen atom (14 * 1 = 14 oxygen atoms). Together, there are 24 + 14 = 38 oxygen atoms on the right side.
Now, the equation is balanced, with 2 moles of C6H14 reacting with 19 moles of O2 to produce 12 moles of CO2 and 14 moles of H2O.


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