Question

Al2S3+Pb(NO3)2=Полное, ионное и скороченое.​

Answer 1

Al2S3 + 3Pb(NO3)2 = 2Al(NO3)3 + 3PbS

2Al(+3) + 3S(-2) + 3Pb(+2) + 6NO3(-) = 2Al(+3) + 6NO3(-) + 3PbS

3S(-2) + 3Pb(+2) = 3PbS

S(-2) + Pb(+2) = 3PbS

Answer 2

To balance the chemical equation Al2S3 + Pb(NO3)2, first, let's write the unbalanced equation:

Al2S3 + Pb(NO3)2 → ?

Now, let's balance the equation step by step:

1. Start with the elements that appear in only one compound on each side of the equation: Al2S3 + Pb(NO3)2 → Al2S3 + Pb(NO3)2

2. Balance the metal atoms (Al and Pb) by adjusting the coefficients: 2 Al2S3 + 3 Pb(NO3)2 → Al2S3 + Pb(NO3)2

3. Balance the non-metal atoms (S and N): 2 Al2S3 + 3 Pb(NO3)2 → Al2S3 + 3 Pb(NO3)2

4. Now, balance the nitrate (NO3-) and sulfate (SO4^2-) ions as a whole. The nitrate ion (NO3-) has a -1 charge, and the sulfate ion (SO4^2-) has a -2 charge. Since we have three nitrate ions on the right side and one sulfate ion on the left side, we need to balance them: 2 Al2S3 + 3 Pb(NO3)2 → Al2S3 + 3 PbSO4

The balanced equation is: 2 Al2S3 + 3 Pb(NO3)2 → Al2S3 + 3 PbSO4

Ionic equation: 2 Al^3+ + 6 S^2- + 3 Pb^2+ + 6 NO3^- → 2 Al^3+ + 6 S^2- + 3 PbSO4

Net ionic equation: 6 NO3^- + 3 Pb^2+ → 3 PbSO4

In the net ionic equation, the spectator ions (Al^3+ and S^2-) are canceled out since they appear on both sides of the equation with the same charges and quantities.