Question

Cu(No3)2+Ba(OH)2= Al+CuCl2= MgSO4+NaOH= CuCl2+AgNo3= Mg+AlCl3=

Answer 1

Ответ:

1)Cu(NO3)2 +Ba(OH)2=Cu(OH)2+Ba(NO3)2

2)2Al+3CuCl2=3Cu+2AlCl3

3)MgSO4 +2NaOH =Na2SO4+Mg(OH)2

4)CuCl2+2AgNO3=Cu(NO3)2+2AgCl

5)3Mg+2AlCl3=2Al+3MgCl2

Answer 2

It looks like you've provided a list of chemical reactions. I'll help you balance the equations and provide information about each reaction:

1. Cu(NO3)2 + Ba(OH)2 → Cu(OH)2 + Ba(NO3)2 This is a double displacement reaction that forms a precipitate of copper(II) hydroxide and barium nitrate.

2. 2 Al + 3 CuCl2 → 2 AlCl3 + 3 Cu This is a single displacement reaction where aluminum displaces copper from copper chloride, forming aluminum chloride and releasing copper metal.

3. MgSO4 + 2 NaOH → Mg(OH)2 + Na2SO4 This is another double displacement reaction that forms magnesium hydroxide and sodium sulfate.

4. CuCl2 + 2 AgNO3 → 2 AgCl + Cu(NO3)2 This reaction forms a white precipitate of silver chloride and regenerates copper(II) nitrate.

5. 2 Mg + AlCl3 → 2 Al + 3 MgCl2 This is a single displacement reaction where magnesium displaces aluminum from aluminum chloride, forming aluminum metal and magnesium chloride.

Please note that in chemical reactions, the number of atoms of each element should be the same on both sides of the equation. This is achieved through balancing the coefficients of the reactants and products. If you need further assistance or have more questions about these reactions, feel free to ask!