Question

Cu(OH)2+NaOH=Fe+CuSO4=Zn+HCl=Na2O+P2O5=​

Answer 1

Ответ:

1  Cu(OH)2 + NaOH = Na2[Cu(OH)4

2 Fe + CuSO4 → Cu + FeSO4

3 Zn + HCl = ZnCl2 + H2

4 Na2O + P2O5 = Na3PO4

Объяснение:

Answer 2

Let's go through each reaction step by step:

1. Cu(OH)2 + NaOH: When copper(II) hydroxide (Cu(OH)2) reacts with sodium hydroxide (NaOH), it undergoes a double displacement reaction. The balanced equation for this reaction is: Cu(OH)2 + 2NaOH → Na2Cu(OH)4

2. Fe + CuSO4: Iron (Fe) reacts with copper sulfate (CuSO4) in a single displacement reaction. The balanced equation for this reaction is: Fe + CuSO4 → FeSO4 + Cu

3. Zn + HCl: Zinc (Zn) reacts with hydrochloric acid (HCl) in a single displacement reaction. The balanced equation for this reaction is: Zn + 2HCl → ZnCl2 + H2

4. Na2O + P2O5: Sodium oxide (Na2O) reacts with diphosphorus pentoxide (P2O5) in a combination reaction. The balanced equation for this reaction is: 2Na2O + P2O5 → 2NaPO3

Please note that the reactants and products in these equations are balanced according to stoichiometry.