Question

СН4 → С2Н2 → С6Н6 → С6Н5СІ → С6Н5ОН → С6Н2ОНBr3

Answer 1

Ответ:

2CH4-->C2H2+3H2

3C2H2-->C6H6

C6H6+CL2-->C6H5CL+HCL

C6H5CL+NaOH-->C6H5OH+NaCL

C6H5OH+3Br2-->C6H2OHBr3+3HBr

Объяснение:

Answer 2

It seems like you've provided a sequence of chemical reactions involving different compounds. This sequence appears to involve the transformation of methane (CH4) into various organic compounds. I'll break down each step of the sequence for you:

1. CH4 (Methane) → C2H2 (Ethyne or Acetylene): Methane undergoes a reaction to form ethyne (also known as acetylene), which is an unsaturated hydrocarbon with a triple bond between the carbon atoms.

2. C2H2 (Ethyne) → C6H6 (Benzene): Ethyne molecules can undergo a series of reactions to form benzene, a cyclic aromatic hydrocarbon with a stable ring structure.

3. C6H6 (Benzene) → C6H5Cl (Chlorobenzene): Benzene reacts with chlorine gas (Cl2) to form chlorobenzene, where one of the hydrogen atoms in the benzene ring is replaced by a chlorine atom.

4. C6H5Cl (Chlorobenzene) → C6H5OH (Phenol): Chlorobenzene can be converted to phenol through a reaction that replaces the chlorine atom with a hydroxyl group (OH), resulting in the formation of phenol.

5. C6H5OH (Phenol) → C6H2OBr3 (2,4,6-Tribromophenol): Phenol reacts with bromine (Br2) to introduce bromine atoms into the phenol ring. In this case, three bromine atoms are added to specific positions on the phenol ring, resulting in 2,4,6-tribromophenol.

It looks like you've outlined a series of chemical reactions that lead to the formation of 2,4,6-tribromophenol from methane. Keep in mind that these reactions represent a simplified overview, and the actual reaction conditions, mechanisms, and intermediates may vary depending on the specific reaction conditions used in the laboratory.