Question

1.Fe(OH)3-->Fe2O3+H2O 2.AL2O3+H2SO4-->AL(SO4)3+H2O3.HCL+Cr2O3-->CrCL3+H2O4.Na+H2O-->NaOH+H25.AL+O2-->AL2O36.ALCL3+NaOH-->AL(OH)3+NaCL7.FeO3+HNO3-->Fe(WO3)3+H2O8.AL+L2-->ALI39.Fe2O3+H2-->Fe+H2O​

Answer 1

Ответ:

Объяснение:

1. 2Fe(OH)3-->Fe2O3+3H2O

2. AL2O3+6H2SO4-->2AL(SO4)3+6H2O

3. 6HCL+Cr2O3-->2CrCL3+3H2O

4. 2Na+2H2O-->2NaOH+H2

5. 4AL+3O2-->2AL2O3

6. ALCL3+3NaOH-->AL(OH)3+3NaCL

7. FeO3+ 3HNO3-->Fe(NO3)3+ 3H2O

8. 2AL+3L2-->2ALI3

9. Fe2O3+3H2-->2Fe+3H2O​

Answer 2

It seems like you've provided a list of chemical reactions. Here's a breakdown of each reaction:

1. Fe(OH)3 → Fe2O3 + H2O Iron(III) hydroxide decomposes to form iron(III) oxide (ferric oxide) and water.

2. Al2O3 + H2SO4 → Al2(SO4)3 + H2O Aluminum oxide reacts with sulfuric acid to produce aluminum sulfate and water.

3. HCl + Cr2O3 → CrCl3 + H2O Hydrochloric acid reacts with chromium(III) oxide to form chromium(III) chloride and water.

4. Na + H2O → NaOH + H2 Sodium metal reacts with water to produce sodium hydroxide and hydrogen gas.

5. 2Al + O2 → 2Al2O3 Aluminum reacts with oxygen to form aluminum oxide. Note that the balanced equation should have a coefficient of 4 in front of Al to balance the equation.

6. AlCl3 + 3NaOH → Al(OH)3 + 3NaCl Aluminum chloride reacts with sodium hydroxide to produce aluminum hydroxide and sodium chloride.

7. Fe2O3 + 6HNO3 → 2Fe(NO3)3 + 3H2O Iron(III) oxide reacts with nitric acid to produce iron(III) nitrate and water.

8. Al + I2 → AlI3 Aluminum reacts with iodine to produce aluminum iodide.

9. Fe2O3 + 3H2 → 2Fe + 3H2O Iron(III) oxide reacts with hydrogen gas to produce iron and water.

Please note that chemical reactions should be balanced properly, meaning that the number of atoms of each element should be the same on both sides of the arrow. The coefficients in front of each chemical species indicate the stoichiometry of the reaction.