Question

NaCl+KOH →Fe+CuS04Ca(OH)2+HNO3 →FeCl2+NaOH-→​

Answer 1

Ответ:

NaCl+KOH ≠

Fe + CuSO4 → FeSO4 + Cu

Ca(OH)2 + 2HNO3 → Ca(NO3)2 + 2H2O

FeCl2 + 2NaOH (разб. р-р)→ Fe(OH)2 + 2NaCl

Объяснение:

Answer 2

It seems like you've provided a series of chemical reactions. Let's break them down step by step:

1. NaCl + KOH:

   • This reaction would produce salt (NaCl) and water (H2O) since sodium hydroxide (KOH) reacts with hydrochloric acid (HCl) from the dissociation of NaCl to form water and salt.

2. Fe + CuSO4:

   • This reaction involves iron (Fe) and copper sulfate (CuSO4). It can result in the displacement of copper by iron, leading to the formation of iron sulfate (FeSO4) and copper (Cu).

3. Ca(OH)2 + HNO3:

   • Calcium hydroxide (Ca(OH)2) reacts with nitric acid (HNO3) to produce calcium nitrate (Ca(NO3)2) and water (H2O).

4. FeCl2 + NaOH:

   • Iron chloride (FeCl2) reacts with sodium hydroxide (NaOH) to produce iron hydroxide (Fe(OH)2) and sodium chloride (NaCl).

It appears that you have a series of separate reactions. If you intended to create a continuous reaction sequence, please provide more information about the context or conditions for these reactions, as well as the reactant quantities and expected products for each step.