Question

39. Обчисліть масу, об'єм (н. у.), кількість речовини, кіль- кість молекул кисню та кількість атомів Оксигену, що утворяться при розкладанні пероксиду гідрогену кількіс- тю речовини 6 моль.

Answer 1

Ответ:

Объяснение:

2H2O2=2H2O+O2

Mr - Молекулярная масса 32г/моль

n количества вещества

n(O2)=1/2n(H2O2)=3моль

V(O2)=n(O2)*Vm=3*22.4=67.2л

Молярный объем 1 моля газа при нормальных условиях всегда одинаков и равен 22,4 л /моль

Масса : m(O2)=n(O2)*Mr(O2)=3*32=96г

Число частиц газа в молекулах

N=n(O2)*Na=3*6.02*10^23=18,06*10^23=1,806*10^24

Физическая величина Na называется постоянной Авогадро. Один моль любого вещества содержит 6,02*10 в степени 23 частиц.

Answer 2

Calculation of Mass, Volume, Amount of Substance, Number of Molecules, and Number of Oxygen Atoms in the Decomposition of Hydrogen Peroxide

To calculate the mass, volume, amount of substance, number of molecules, and number of oxygen atoms formed during the decomposition of hydrogen peroxide, we need to use the molar ratios and the molar mass of hydrogen peroxide.

The chemical equation for the decomposition of hydrogen peroxide (H2O2) is:

2 H2O2 -> 2 H2O + O2

From this equation, we can determine the molar ratios between hydrogen peroxide, water, and oxygen. The molar ratio between hydrogen peroxide and oxygen is 2:1, meaning that for every 2 moles of hydrogen peroxide, 1 mole of oxygen is produced.

Given that we have 6 moles of hydrogen peroxide, we can calculate the corresponding values:

1. Mass: The molar mass of hydrogen peroxide (H2O2) is approximately 34.02 g/mol [[1]]. To calculate the mass, we multiply the molar mass by the number of moles:

Mass = 34.02 g/mol * 6 mol = 204.12 g

Therefore, the mass of 6 moles of hydrogen peroxide is approximately 204.12 grams.

2. Volume: The volume of a gas can be calculated using the ideal gas law, which states that the volume is directly proportional to the number of moles of gas at constant temperature and pressure. However, the given information does not provide the temperature and pressure conditions. Therefore, we cannot calculate the volume without this information.

3. Amount of Substance: The amount of substance is given as 6 moles, which is the number of moles of hydrogen peroxide provided in the question.

4. Number of Molecules: Avogadro's number (6.022 x 10^23) represents the number of particles (atoms, molecules, or ions) in one mole of a substance. To calculate the number of molecules, we multiply Avogadro's number by the number of moles:

Number of Molecules = 6.022 x 10^23 molecules/mol * 6 mol = 3.6132 x 10^24 molecules

Therefore, the number of molecules formed during the decomposition of 6 moles of hydrogen peroxide is approximately 3.6132 x 10^24 molecules.

5. Number of Oxygen Atoms: Since the molar ratio between hydrogen peroxide and oxygen is 2:1, the number of oxygen atoms will be half the number of molecules of hydrogen peroxide. Therefore, we can calculate the number of oxygen atoms as follows:

Number of Oxygen Atoms = (1/2) * Number of Molecules

Number of Oxygen Atoms = (1/2) * 3.6132 x 10^24 molecules = 1.8066 x 10^24 atoms

Therefore, the number of oxygen atoms formed during the decomposition of 6 moles of hydrogen peroxide is approximately 1.8066 x 10^24 atoms.

Please note that the volume calculation requires additional information about the temperature and pressure conditions. Without this information, we cannot provide a specific value for the volume.