Question

Какая масса магния прореагирует без остатка с 12 г кислорода, если они соединяются в отношении масс 3:2? Точность вычислений — до десятых.

Answer 1

Масса серы больше массы магния. Значит M(S)/M(Mg)=4/3

40/x=4/3

x=30

Answer 2

Calculation of Magnesium and Oxygen Reaction

To determine the mass of magnesium that will react completely with 12 g of oxygen, we need to consider the stoichiometry of the reaction. The given ratio of masses between magnesium and oxygen is 3:2. This means that for every 3 units of magnesium, we have 2 units of oxygen.

Let's assume the mass of magnesium is 3x and the mass of oxygen is 2x. According to the given ratio, we have:

Mass of magnesium = 3x Mass of oxygen = 2x

We are given that the mass of oxygen is 12 g. So we can set up the following equation:

2x = 12

Solving for x, we find:

x = 12 / 2 = 6

Now we can substitute the value of x back into the equation to find the mass of magnesium:

Mass of magnesium = 3x = 3 * 6 = 18 g

Therefore, 18 grams of magnesium will react completely with 12 grams of oxygen when they combine in a ratio of 3:2.

Please note that the above calculation assumes ideal conditions and does not take into account any potential side reactions or impurities.