Question

Задание 4 Реакция идет по уравнению: CuSO4 + 2NaOH = Cu(OH)2 + Na,SO4. Найти химическое количество и массу щелочи (NaOH), необходимой для реакции с 95 г сульфата меди (Cuѕo4)​

Answer 1

Решение на фото

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Answer 2

Reaction Equation and Stoichiometry

The given reaction equation is:

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

According to the balanced equation, 1 mole of CuSO4 reacts with 2 moles of NaOH to produce 1 mole of Cu(OH)2 and 1 mole of Na2SO4.

Calculating the Chemical Amount of NaOH

To find the chemical amount of NaOH required to react with 95 g of CuSO4, we need to convert the mass of CuSO4 to moles using its molar mass.

The molar mass of CuSO4 can be calculated as follows: - Atomic mass of Cu = 63.55 g/mol - Atomic mass of S = 32.07 g/mol - Atomic mass of O (4 atoms) = 16.00 g/mol - Molar mass of CuSO4 = (63.55 g/mol) + (32.07 g/mol) + (16.00 g/mol * 4) = 159.61 g/mol

Now, we can calculate the number of moles of CuSO4: - Moles of CuSO4 = Mass of CuSO4 / Molar mass of CuSO4 = 95 g / 159.61 g/mol = 0.595 mol

Since the stoichiometric ratio between CuSO4 and NaOH is 1:2, we can calculate the moles of NaOH required: - Moles of NaOH = 2 * Moles of CuSO4 = 2 * 0.595 mol = 1.19 mol

Calculating the Mass of NaOH

To find the mass of NaOH required, we can use its molar mass, which is 39.997 g/mol.

The mass of NaOH can be calculated as follows: - Mass of NaOH = Moles of NaOH * Molar mass of NaOH = 1.19 mol * 39.997 g/mol = 47.6 g

Therefore, the mass of NaOH required to react with 95 g of CuSO4 is approximately 47.6 grams.

Please note that the molar mass of NaOH is rounded to four decimal places for the calculation.