Question

ПОМОГИТЕ РЕШИТЬ!!! Большинство элементов периодической системы способно проявлять разную валентность в различных соединениях. Так, элемент X при взаимодействии с кислородом образует два газообразных оксида, причем валентность в одном из них в два раза больше, чем в другом. Также известно, что молярная масса более тяжелого оксида в 1.57 раз превышает молярную массу более легкого. Молекулы обоих оксидов содержат одинаковое количество атомов неизвестного элемента. Определите элемент X. В ответ запишите порядковый номер элемента.

Answer 1

скорее всего это углерод

.

CO - несолеобразующий  

CO2 - кислотный

Answer 2

Ответ:

Это углерод. Его порядковый номер 6.

Answer 3

Element X and its Valency

The question states that element X can exhibit different valencies in different compounds. When interacting with oxygen, element X forms two gaseous oxides, with one oxide having a valency twice that of the other. Additionally, the molar mass of the heavier oxide is 1.57 times greater than the molar mass of the lighter oxide. The molecules of both oxides contain the same number of atoms of element X.

To determine the identity of element X, we need to analyze the given information.

Analysis of the Given Information

1. Element X forms two gaseous oxides when reacting with oxygen, with one oxide having a valency twice that of the other. 2. The molar mass of the heavier oxide is 1.57 times greater than the molar mass of the lighter oxide. 3. The molecules of both oxides contain the same number of atoms of element X.

Determining the Identity of Element X

Let's assume the valency of element X in the lighter oxide is n. Therefore, the valency of element X in the heavier oxide would be 2n.

Based on the given information, we can set up the following equations:

Equation 1: The molar mass of the heavier oxide is 1.57 times greater than the molar mass of the lighter oxide. Equation 2: The molecules of both oxides contain the same number of atoms of element X.

To simplify the equations, let's assume the molar mass of the lighter oxide is m.

According to Equation 1, the molar mass of the heavier oxide would be 1.57m.

According to Equation 2, the number of atoms of element X in both oxides would be the same.

Now, let's consider the possible valencies of element X.

If the valency of element X in the lighter oxide is 1, then the valency of element X in the heavier oxide would be 2.

If the valency of element X in the lighter oxide is 2, then the valency of element X in the heavier oxide would be 4.

If the valency of element X in the lighter oxide is 3, then the valency of element X in the heavier oxide would be 6.

If the valency of element X in the lighter oxide is 4, then the valency of element X in the heavier oxide would be 8.

Based on the given information, we can conclude that the valency of element X in the lighter oxide is 2 and the valency of element X in the heavier oxide is 4.

Therefore, the element X is located in Group 14 of the periodic table, as elements in this group typically exhibit a valency of 2 and 4. The element with atomic number 14 is Silicon (Si).

To summarize: - Element X is Silicon (Si). - The valency of element X in the lighter oxide is 2. - The valency of element X in the heavier oxide is 4.

Please let me know if you need any further clarification or assistance!