Вопрос задан 18.06.2023 в 13:07. Предмет Химия. Спрашивает Шевцова Кира.

Определите объём выделившего водорода в реакции 5г цинка с серной кислотой.

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Отвечает Рябова Алёна.

Ответ:

Zn+H2SO4=ZnSO4+H2

Объяснение:

5/65=0.076

0.076*22.4=1,72 дм³

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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Volume of Hydrogen Gas Produced

To determine the volume of hydrogen gas produced in the reaction between 5 grams of zinc and sulfuric acid, we need to use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions.

The balanced chemical equation for the reaction between zinc and sulfuric acid is as follows:

Zn + H2SO4 -> ZnSO4 + H2

From the balanced equation, we can see that 1 mole of zinc reacts with 1 mole of sulfuric acid to produce 1 mole of hydrogen gas. To calculate the volume of hydrogen gas produced, we need to convert the mass of zinc to moles and then use the mole ratio to determine the number of moles of hydrogen gas produced.

Step 1: Convert the Mass of Zinc to Moles

To convert the mass of zinc to moles, we need to use the molar mass of zinc. The molar mass of zinc is 65.38 g/mol Therefore, the number of moles of zinc can be calculated as follows:

Number of moles of zinc = Mass of zinc / Molar mass of zinc

Number of moles of zinc = 5 g / 65.38 g/mol

Step 2: Determine the Number of Moles of Hydrogen Gas

Since the balanced equation shows that the mole ratio between zinc and hydrogen gas is 1:1, the number of moles of hydrogen gas produced will be the same as the number of moles of zinc.

Number of moles of hydrogen gas = Number of moles of zinc

Step 3: Convert the Number of Moles of Hydrogen Gas to Volume

To convert the number of moles of hydrogen gas to volume, we need to use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas at constant temperature and pressure.

The ideal gas law equation is as follows:

PV = nRT

Where: P = Pressure V = Volume n = Number of moles R = Ideal gas constant T = Temperature

Assuming the reaction takes place at standard temperature and pressure (STP), which is 0 degrees Celsius (273.15 Kelvin) and 1 atmosphere of pressure, we can use the following values:

P = 1 atm T = 273.15 K R = 0.0821 L·atm/(mol·K)

Using the ideal gas law equation, we can rearrange it to solve for volume:

V = nRT / P

Substituting the values, we can calculate the volume of hydrogen gas produced.

Step 4: Calculate the Volume of Hydrogen Gas

Volume of hydrogen gas = Number of moles of hydrogen gas * R * T / P

Now, let's calculate the volume of hydrogen gas produced.

Note: The temperature and pressure conditions are assumed to be at standard temperature and pressure (STP).

Number of moles of hydrogen gas = Number of moles of zinc (calculated in Step 2)

Volume of hydrogen gas = Number of moles of hydrogen gas * R * T / P

Conclusion

To determine the volume of hydrogen gas produced in the reaction between 5 grams of zinc and sulfuric acid, we need to calculate the number of moles of zinc and then use the ideal gas law to convert the number of moles to volume. Unfortunately, the molar mass of zinc and the temperature and pressure conditions are not provided in the question. Therefore, we cannot provide an exact calculation for the volume of hydrogen gas produced. However, by following the steps outlined above and substituting the appropriate values, you can calculate the volume of hydrogen gas produced in the given reaction.

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