Question

Определить молярную концентрацию раствора серной кислоты, полученного при смешивании 25 мл 10-молярного раствора серной кислоты и 225 мл воды.​

Answer 1

Ответ:

Дано:                               Решение:

V(p. H2SO4) = 25 мл                  1) n (H2SO4) - ? В 1000 мл – 10 моль

C(H2SO4) = 10 моль/л                     в 25 мл – х моль

V(H2O) = 225мл                                 х = 0,25 моль

C(H2SO4) = ?                         2)  V(р-ра) = 225 мл + 25 мл = 250 мл

                                               3) C(H2SO4) - ? В 250 мл – 0,25 моль

                                                  в 1000 мл – х моль

                                                        х = 1 моль/л

                                              Ответ: С = 1 моль/л.ние:

Answer 2

Calculation of Molar Concentration of Sulfuric Acid Solution

To determine the molar concentration of the sulfuric acid solution obtained by mixing a 25 mL 10-molar sulfuric acid solution with 225 mL of water, we can use the formula:

M1V1 = M2V2

Where: - M1 is the initial molar concentration of the sulfuric acid solution - V1 is the initial volume of the sulfuric acid solution - M2 is the final molar concentration of the sulfuric acid solution - V2 is the final volume of the sulfuric acid solution

In this case, the initial molar concentration (M1) is 10 M, the initial volume (V1) is 25 mL, and the final volume (V2) is the sum of the initial volume and the volume of water added (225 mL). We need to solve for the final molar concentration (M2).

Using the formula, we can calculate the final molar concentration as follows:

M2 = (M1 * V1) / V2

Substituting the given values:

M2 = (10 M * 25 mL) / (25 mL + 225 mL)

M2 = (250 M mL) / 250 mL

M2 = 1 M

Therefore, the molar concentration of the sulfuric acid solution obtained by mixing a 25 mL 10-molar sulfuric acid solution with 225 mL of water is 1 M.