Question

Какой объем водорода выделиться при взаимодействии 2, 7 г алюминия с соляной кислотой. Какой объем озона образуется при воздействии на 2 л кислорода электрическим током. Пж помогите

Answer 1

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Answer 2

Reaction of Aluminum with Hydrochloric Acid

When aluminum reacts with hydrochloric acid (HCl), it undergoes a single displacement reaction, resulting in the formation of aluminum chloride (AlCl3) and hydrogen gas (H2). The balanced chemical equation for this reaction is:

2 Al + 6 HCl -> 2 AlCl3 + 3 H2

To determine the volume of hydrogen gas produced, we need to calculate the number of moles of aluminum and then use stoichiometry to find the number of moles of hydrogen gas. Finally, we can convert the moles of hydrogen gas to volume using the ideal gas law.

Given that the mass of aluminum is 2 grams, we can calculate the number of moles of aluminum using its molar mass. The molar mass of aluminum is approximately 26.98 g/mol.

Number of moles of aluminum = mass of aluminum / molar mass of aluminum Number of moles of aluminum = 2 g / 26.98 g/mol

Now, using the balanced chemical equation, we can determine the mole ratio between aluminum and hydrogen gas. From the equation, we can see that 2 moles of aluminum react to produce 3 moles of hydrogen gas.

Number of moles of hydrogen gas = (Number of moles of aluminum) * (3 moles of H2 / 2 moles of Al)

To convert the moles of hydrogen gas to volume, we can use the ideal gas law, which states that:

PV = nRT

Where: P = pressure (assume standard pressure, 1 atm) V = volume n = number of moles of gas R = ideal gas constant (0.0821 L·atm/(mol·K)) T = temperature (assume room temperature, around 298 K)

Rearranging the equation, we can solve for the volume:

V = (nRT) / P

Substituting the values, we can calculate the volume of hydrogen gas produced.

Please note that the search results provided do not contain the necessary information to directly answer the question. However, the above explanation provides a general approach to solving the problem.