Question

Медь → оксид меди (II) → хлорид меди (II) → гидроксид меди (II) → оксид меди (II)

Answer 1

$\boxed{\bf Cu \to CuO \to CuCl_2 \to Cu(OH)_2 \to CuO}$

$\sf 1)~2Cu + O_2 \to 2CuO.$

$\sf 2)~CuO + 2HCl \to CuCl_2 + H_2O.$

$\sf 3) ~CuCl_2 + 2NaOH \to Cu(OH)_2\downarrow + 2NaCl.$

$\sf 4)~Cu(OH)_2 \xrightarrow{t^{\circ}C} CuO + H_2O\uparrow.$

Answer 2

Ответ:

решение приложено ниже со степенями окисления

Объяснение:

Answer 3

Chemical Reactions:

The given chemical reaction involves the transformation of copper (Cu) through several compounds: copper oxide (CuO), copper chloride (CuCl2), copper hydroxide (Cu(OH)2), and back to copper oxide (CuO).

The reaction can be represented as follows: Copper (Cu) → Copper Oxide (CuO) → Copper Chloride (CuCl2) → Copper Hydroxide (Cu(OH)2) → Copper Oxide (CuO)

Explanation:

1. Copper (Cu) reacts with oxygen (O2) to form copper oxide (CuO). 2. Copper oxide (CuO) reacts with hydrochloric acid (HCl) to form copper chloride (CuCl2). 3. Copper chloride (CuCl2) reacts with sodium hydroxide (NaOH) to form copper hydroxide (Cu(OH)2). 4. Copper hydroxide (Cu(OH)2) can decompose to form copper oxide (CuO) when heated.

It's important to note that the given reaction is a simplified representation and may not take into account specific reaction conditions or stoichiometry.

Conclusion:

The given chemical reaction involves the transformation of copper through various compounds, including copper oxide, copper chloride, and copper hydroxide. The reaction sequence is as follows: copper reacts with oxygen to form copper oxide, which then reacts with hydrochloric acid to form copper chloride. Copper chloride further reacts with sodium hydroxide to form copper hydroxide, which can decompose to form copper oxide when heated.