Question

18*, Серную кислоту получают пирита по схеме: Из 140 г пирита получено 180 г кислоты. Учитывая, что об- щий выход реакции равен 98,9 %, найдите массовую долю серы в пирите.

Answer 1

Ответ:

1) Найдем м.д. серы в пирите FeS2  в соот-ии с ф-ой: (64/120)*100 = 53.33%

2) масса H2SO4  сос-т: (140/120)*2*98 = 228.67 г, практический выход сос-л 180/0.989 = 182 г

3) т.о. м.д. серы в пирите сос-т 53.33*(182/228.67) = 42.4457%

Объяснение:

Answer 2

Calculation of Sulfur Mass Fraction in Pyrite

To find the mass fraction of sulfur in pyrite, we can use the information given in the problem statement. According to the problem, 140 g of pyrite yields 180 g of sulfuric acid, and the overall yield of the reaction is 98.9%.

Let's calculate the mass fraction of sulfur in pyrite using the given information:

1. Calculate the mass of sulfur in the sulfuric acid: - Mass of sulfuric acid = 180 g - Since sulfuric acid (H2SO4) contains 1 sulfur atom, the molar mass of sulfur in sulfuric acid is 32.07 g/mol. - Therefore, the mass of sulfur in 180 g of sulfuric acid is (32.07 g/mol) * (180 g / 98.09 g/mol) = 58.89 g.

2. Calculate the mass of pyrite: - Mass of pyrite = 140 g

3. Calculate the mass fraction of sulfur in pyrite: - Mass fraction of sulfur = (Mass of sulfur in pyrite / Mass of pyrite) * 100% - Mass fraction of sulfur = (58.89 g / 140 g) * 100% = 42.07%

Therefore, the mass fraction of sulfur in pyrite is approximately 42.07%.

Please note that the sources provided did not contain specific information related to the calculation of the mass fraction of sulfur in pyrite. The calculation was performed based on the given information and general knowledge of stoichiometry.