Question

Вычислите массу и количество вещества (моль) кислорода, если в результате реакции получилось 8грамм Fe2O3?​

Answer 1

Ответ:

М(Fe2O3) = 56•2+16•3=160г/моль

m(O3)= 48:160= 0,3 моль

Answer 2

Calculation of Mass and Moles of Oxygen

To calculate the mass and number of moles of oxygen in the reaction, we need to determine the molar mass of Fe2O3 (iron(III) oxide) and use stoichiometry.

The molar mass of Fe2O3 can be calculated by adding up the atomic masses of its constituent elements. The atomic masses of iron (Fe) and oxygen (O) are approximately 55.85 g/mol and 16.00 g/mol, respectively. Since there are two iron atoms and three oxygen atoms in Fe2O3, the molar mass of Fe2O3 is:

Molar mass of Fe2O3 = (2 * atomic mass of Fe) + (3 * atomic mass of O) = (2 * 55.85 g/mol) + (3 * 16.00 g/mol) = 111.70 g/mol + 48.00 g/mol = 159.70 g/mol

Now, we can use the molar mass of Fe2O3 to calculate the number of moles of oxygen in 8 grams of Fe2O3. We'll assume that all the oxygen in Fe2O3 is converted to oxygen gas (O2) during the reaction.

Number of moles of oxygen = (mass of Fe2O3) * (1 mole of O2 / molar mass of Fe2O3) = 8 g * (1 mol O2 / 159.70 g) ≈ 0.050 mol O2

Therefore, the mass of oxygen in the reaction is 8 grams, and the number of moles of oxygen is approximately 0.050 moles.