Question

ПОМОГИТЕ ПОЖАЛУЙСТА ЭТО КОНТРОЛЬНАЯ Проанализируйте приведенное уравнение химической реакции 2H2(г) + О2 = 2H2O(г) И ответьте на следующие вопросы а) В каких объемных отношениях находятся водород и кислород и как вы это определили? б) Какой объем паров воды образуется если в реакцию вступит 5 л кислорода

Answer 1

Ответ:

а)азот і водень 1:3(1 моль і 3 моль)

100л/22,4=х/44,8

х=200л

Answer 2

Ответ:

Объяснение:
a) Пусть V(O2) = 1 л, тогда v(H2) = 2 л. (т.к. коэффициент перед h2 - 2)
Отношение объемов их: V(O2)/V(H2) = 1/2 = 0,5
б) n(O2) = 5/22,4 = 0,223 моль.
n(H2O) = 2n(O2) = 0,223 * 2 = 0,446 моль.
V(H2O) = 0,446 * 22,4 = 10 л.

Answer 3

Analysis of the Chemical Equation

The given chemical equation is: 2H2(g) + O2 = 2H2O(g)

a) The question asks about the volumetric ratios of hydrogen and oxygen in the reaction and how this can be determined.

To determine the volumetric ratios, we can use the coefficients in the balanced chemical equation. The coefficients represent the number of moles of each substance involved in the reaction. In this case, the coefficient of H2 is 2, and the coefficient of O2 is 1.

According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, the ratio of the volumes of hydrogen to oxygen in the reaction is the same as the ratio of their coefficients. In this case, the volumetric ratio of hydrogen to oxygen is 2:1.

b) The question asks for the volume of water vapor formed when 5 L of oxygen reacts.

To determine the volume of water vapor formed, we need to use the stoichiometry of the reaction. The balanced equation tells us that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water vapor.

First, we need to convert the given volume of oxygen to moles. Since the molar volume of any gas at standard temperature and pressure (STP) is 22.4 L/mol, we can use the following conversion:

5 L O2 * (1 mol O2 / 22.4 L O2) = 0.2232 mol O2

According to the stoichiometry of the reaction, 1 mole of oxygen reacts to produce 2 moles of water vapor. Therefore, the number of moles of water vapor formed is:

0.2232 mol O2 * (2 mol H2O / 1 mol O2) = 0.4464 mol H2O

Finally, we can convert the moles of water vapor to volume using the molar volume at STP:

0.4464 mol H2O * (22.4 L H2O / 1 mol H2O) = 9.9984 L H2O

Therefore, if 5 L of oxygen reacts, approximately 10 L of water vapor will be formed.

Please note that the calculations provided are based on the given information and assumptions.