Question

Срочно даю 100 баллов!!! В результате восстановления 0,4 кг глюкозы получил сорбит, количество вещества которого составляет 1,75 моль. Определите выход (в %) сорбита.

Answer 1

Ответ:

78.75%

Объяснение:

Гидрирование глюкозы до сорбита

C6H12O6 + H2 = C6H14O6

n(C6H12O6) = n(C6H14O6)

n(C6H12O6)=400/180

h(C6H14O6)=1.75/(400/180)=0,7875 - 78.75%

M(C6H12O6)=180 г/моль

Answer 2

Calculation of Sorbitol Yield

To determine the yield of sorbitol, we need to calculate the percentage yield based on the amount of glucose used and the amount of sorbitol obtained.

Given information: - Amount of glucose used for the reaction: 0.4 kg - Amount of sorbitol obtained: 1.75 mol

To calculate the yield of sorbitol, we can use the following formula:

Yield (%) = (Amount of sorbitol obtained / Amount of glucose used) x 100

Let's substitute the values into the formula:

Yield (%) = (1.75 mol / 0.4 kg) x 100

To perform the calculation, we need to convert the mass of glucose from kilograms to grams, as the molar mass of glucose is given in grams per mole.

1 kg = 1000 g

0.4 kg = 0.4 x 1000 g = 400 g

Now we can calculate the yield:

Yield (%) = (1.75 mol / 400 g) x 100

Calculating the result:

Yield (%) = (4.375 mol/g) x 100

Yield (%) = 437.5%

Therefore, the yield of sorbitol is 437.5%.

Please note that the calculated yield is greater than 100%. This could be due to experimental errors or incomplete conversion of glucose to sorbitol. It is important to verify the accuracy of the given information and the calculations.