Question

3. Определите массу и объем (н. у.) 6,02∙1024 молекул азота. Рассчитайте относительную плотность азота по воздуху и гелию (3 балла).

Answer 1

Объяснение:

Дано

М(N2)=28

M(возд)=29

М(Не)=4

V°=22,4

6,02*10^24=60,2*10^23

n=60,2*10^23/6,02*10^23=10моль

V=22,4*10=224л

m=28*10=280г

D=M1/M2

1) 280/2=140

2) 280/29=9,65

Answer 2

Calculation of Mass and Volume of Nitrogen Molecules

To calculate the mass and volume of 6.02 x 10^24 molecules of nitrogen, we need to know the molar mass of nitrogen and Avogadro's number.

The molar mass of nitrogen (N2) is approximately 28.0134 grams per mole.

Avogadro's number (NA) is approximately 6.022 x 10^23 molecules per mole.

To calculate the mass of 6.02 x 10^24 molecules of nitrogen, we can use the following formula:

Mass = (Number of molecules / Avogadro's number) x Molar mass

Substituting the values into the formula:

Mass = (6.02 x 10^24 / 6.022 x 10^23) x 28.0134 grams

Simplifying the calculation:

Mass = 10 x 28.0134 grams

Mass = 280.134 grams

Therefore, the mass of 6.02 x 10^24 molecules of nitrogen is approximately 280.134 grams.

To calculate the volume of 6.02 x 10^24 molecules of nitrogen, we need to know the volume occupied by one mole of nitrogen gas at standard temperature and pressure (STP). At STP, one mole of any ideal gas occupies 22.4 liters.

To calculate the volume of 6.02 x 10^24 molecules of nitrogen, we can use the following formula:

Volume = (Number of molecules / Avogadro's number) x Molar volume

Substituting the values into the formula:

Volume = (6.02 x 10^24 / 6.022 x 10^23) x 22.4 liters

Simplifying the calculation:

Volume = 10 x 22.4 liters

Volume = 224 liters

Therefore, the volume of 6.02 x 10^24 molecules of nitrogen is approximately 224 liters.

Calculation of Relative Density of Nitrogen

To calculate the relative density of nitrogen with respect to air and helium, we need to know the densities of nitrogen, air, and helium.

The density of nitrogen at STP is approximately 1.25 grams per liter.

The density of air at STP is approximately 1.225 grams per liter.

The density of helium at STP is approximately 0.1785 grams per liter.

To calculate the relative density of nitrogen with respect to air, we can use the following formula:

Relative Density (Nitrogen/Air) = Density of Nitrogen / Density of Air

Substituting the values into the formula:

Relative Density (Nitrogen/Air) = 1.25 grams per liter / 1.225 grams per liter

Relative Density (Nitrogen/Air) ≈ 1.0204

Therefore, the relative density of nitrogen with respect to air is approximately 1.0204.

To calculate the relative density of nitrogen with respect to helium, we can use the following formula:

Relative Density (Nitrogen/Helium) = Density of Nitrogen / Density of Helium

Substituting the values into the formula:

Relative Density (Nitrogen/Helium) = 1.25 grams per liter / 0.1785 grams per liter

Relative Density (Nitrogen/Helium) ≈ 7.0034

Therefore, the relative density of nitrogen with respect to helium is approximately 7.0034.

Please note that the values provided are approximate and may vary slightly depending on the specific conditions and sources used for density measurements.

Let me know if there's anything else I can help you with!