
KCLO3+P2O3+H2- H3PO4KCL уравняйте пожалуйста


Ответы на вопрос

Ответ:
4KCL+O3+P2O3+3H2 = 2H3PO+4KCL
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Balancing the Chemical Equation
To balance the chemical equation KClO3 + P2O3 + H2 → H3PO4 + KCl, we need to ensure that the same number of each type of atom is present on both sides of the equation.
Balancing Steps
1. Count the Atoms: First, let's count the atoms of each element on both sides of the equation. - Left Side: K: 1, Cl: 1, O: 3, P: 2, H: 2 - Right Side: H: 3, P: 1, O: 4, K: 1, Cl: 1
2. Balancing: We'll start by balancing the elements that appear only once on each side of the equation.
- Phosphorus (P): There are 2 phosphorus atoms on the left and only 1 on the right. We can balance this by placing a coefficient of 2 in front of the product H3PO4. - Hydrogen (H): There are 2 hydrogen atoms on the left and 3 on the right. We can balance this by placing a coefficient of 3 in front of the reactant H2.
3. Final Balanced Equation: After applying the coefficients, the balanced chemical equation is: ``` KClO3 + P2O3 + 3H2 → 2H3PO4 + KCl ```
This balanced equation ensures that the same number of each type of atom is present on both sides.
I hope this helps! If you have any more questions or need further assistance, feel free to ask.


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