Question

Дано : m(NH3)=1,7г найти n(NH3)-? V(NH3)-?​

Answer 1

Дано:
m(NH3)= 1,7г
Найти:
n(NH3)-?
V(NH3)-?
Решение:
n=m/M
M(NH3)=14+3*1=17 г/моль
n(NH3)= 1,7 г/17 г/моль=0,1 моль


n=V/Vm
Vm(н.у.)= 22,4 л/моль
V=n*Vm
V(NH3)=0,1 моль* 22,4 л/моль=2,24 л
Ответ:n(NH3)=0,1 моль, V(NH3)=2,24 л

Answer 2

I can help you with your chemistry question. Here is a detailed solution:

Given: $$m(\text{NH}_3) = 1.7 \text{ g}$$ Find: $$n(\text{NH}_3)$$ and $$V(\text{NH}_3)$$

To find the amount of substance $$n(\text{NH}_3)$$, we need to use the formula:

$$n(\text{NH}_3) = \frac{m(\text{NH}_3)}{M(\text{NH}_3)}$$

where $$M(\text{NH}_3)$$ is the molar mass of ammonia. To calculate the molar mass, we need to add the atomic masses of nitrogen and hydrogen:

$$M(\text{NH}_3) = M(\text{N}) + 3M(\text{H}) = 14.01 + 3 \times 1.01 = 17.04 \text{ g/mol}$$

Plugging in the values, we get:

$$n(\text{NH}_3) = \frac{1.7}{17.04} = 0.0998 \text{ mol}$$

To find the volume of gas $$V(\text{NH}_3)$$, we need to use the ideal gas law:

$$pV = nRT$$

where $$p$$ is the pressure, $$V$$ is the volume, $$n$$ is the amount of substance, $$R$$ is the universal gas constant, and $$T$$ is the temperature. Assuming standard conditions, we can use the values:

$$p = 1 \text{ atm}$$ $$R = 0.0821 \text{ L atm/mol K}$$ $$T = 273.15 \text{ K}$$

Plugging in the values, we get:

$$V(\text{NH}_3) = \frac{nRT}{p} = \frac{0.0998 \times 0.0821 \times 273.15}{1} = 2.23 \text{ L}$$

Therefore, the answers are:

$$n(\text{NH}_3) = 0.0998 \text{ mol}$$ $$V(\text{NH}_3) = 2.23 \text{ L}$$

I hope this helps you understand the problem. If you have any other questions, feel free to ask me.Ответь+подробно.++Дано+:+m(NH3)=1,7г+найти+n(NH3)-?+V(NH3)-?​+