Question

8. Оксид серы(VI) массой 32 г растворили в 400 г воды. Определите массовую долю (%) H2SO4 в полученном растворе. ПОМОГИТЕ ПОЖАЛУЙСТА ! НЕ ПИШИТЕ ЕСЛИ НЕ ЗНАЕТЕ

Answer 1

Вот как-то так я решила эту задачу

Answer 2

Calculation of the Mass Fraction of H2SO4 in the Solution

To determine the mass fraction of H2SO4 in the solution, we need to consider the molar mass of H2SO4 and the total mass of the solution.

The molar mass of H2SO4 is calculated as follows: - 2 hydrogen atoms (2 H) with a molar mass of 1.008 g/mol each - 1 sulfur atom (1 S) with a molar mass of 32.06 g/mol - 4 oxygen atoms (4 O) with a molar mass of 16.00 g/mol each

Adding these values together, we get: 2(1.008 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.09 g/mol

Now, let's calculate the number of moles of H2SO4 in the 32 g of sulfur oxide (SO3) that was dissolved in the solution. To do this, we divide the mass of SO3 by its molar mass: 32 g / 98.09 g/mol = 0.3267 mol

Since H2SO4 is a strong acid, it completely dissociates in water to produce 2 moles of H+ ions and 1 mole of SO4^2- ions. Therefore, the number of moles of H2SO4 in the solution is twice the number of moles of SO3: 0.3267 mol × 2 = 0.6534 mol

Next, we calculate the total mass of the solution by adding the mass of the water (400 g) to the mass of the sulfur oxide (32 g): 400 g + 32 g = 432 g

Finally, we can calculate the mass fraction of H2SO4 in the solution by dividing the mass of H2SO4 by the total mass of the solution and multiplying by 100%: (0.6534 mol × 98.09 g/mol) / 432 g × 100% ≈ 14.97%

Therefore, the mass fraction of H2SO4 in the obtained solution is approximately 14.97%.

Please note that the above calculation assumes that the sulfur oxide (SO3) completely reacts with water to form H2SO4.