Question

Определите массовую долю кислорода KMnO4

Answer 1

Ответ:

0,4051=50,51%

Объяснение:

w%= относительная атомная масса(16*4) : относительная атомная масса всего вещества(55+39+16*4)
W%= 64:158=0,4051 или 40,51%

Answer 2

Дано:

KMnO4

ω(О)=?

Решение:

Mr(KMnO4) = Ar(K) + Ar(Mn) + 4Ar(O) = 39 + 55 + 4 • 16 = 142

ω= (n∙Ar(O))/(Mr(KMnO4))

ω= (4∙16)/142=0,338 или 33,8%

Ответ: ω= 0,338 или 33,8%

Answer 3

Determining the Mass Fraction of Oxygen in KMnO4

The mass fraction of oxygen in KMnO4 can be determined by calculating the molar mass of KMnO4 and then finding the mass of oxygen in it.

Molar Mass of KMnO4: The molar mass of KMnO4 can be calculated by adding the atomic masses of potassium (K), manganese (Mn), and oxygen (O) in the compound.

The molar mass of potassium (K) is 39.10 g/mol, manganese (Mn) is 54.94 g/mol, and oxygen (O) is 16.00 g/mol.

Therefore, the molar mass of KMnO4 is: Molar mass = (1 * atomic mass of K) + (1 * atomic mass of Mn) + (4 * atomic mass of O)

Calculation: Molar mass of KMnO4 = (1 * 39.10 g/mol) + (1 * 54.94 g/mol) + (4 * 16.00 g/mol)

Molar mass of KMnO4 = 39.10 g/mol + 54.94 g/mol + 64.00 g/mol

Molar mass of KMnO4 = 158.04 g/mol

Mass Fraction of Oxygen: To find the mass fraction of oxygen in KMnO4, we can use the formula: Mass fraction of oxygen = (mass of oxygen / molar mass of KMnO4) * 100%

Calculation: Given that there are 4 oxygen atoms in KMnO4, the mass of oxygen in KMnO4 is: Mass of oxygen = (4 * atomic mass of O)

Mass of oxygen = 4 * 16.00 g/mol

Mass of oxygen = 64.00 g/mol

Now, we can calculate the mass fraction of oxygen: Mass fraction of oxygen = (64.00 g/mol / 158.04 g/mol) * 100%

Result: The mass fraction of oxygen in KMnO4 is approximately 40.51%.

This calculation is based on the molar mass of KMnO4 and the number of oxygen atoms in the compound