Question

СРОЧНО!!!! При взаимодействии алюминия с хлором образуется хлорид алюминия. Рассчитайте количество вещества, массу и объём ( н.у. ) хлора, который потребуется для взаимодействия с 27 г алюминия, содержащего 20% примесей?​

Answer 1

Ответ:

Дано

m( гряз Al) = 27 g

W(пр)  = 20%

--------------------

m(CL2) - ?

n(CL2) - ?

m чист(AL) = 27  - (27* 20% ) / 100% = 21.6 g

2Al + 3CL2-->2AlCL3

M(Al) = 27 g/mol

n(Al) = m/M = 21.6 / 27 = 0.8 mol

2n(Al) = 3n(CL2)

n(CL2) = 0.8 * 3 / 2 = 1.2 mol

M(CL2) = 71 g/mol

m(CL2) = n*M = 1.2 * 71  = 85.2 g

ответ 1.2 моль , 85.2 гр

Объяснение:

Answer 2

Calculation of the Amount, Mass, and Volume of Chlorine Required to React with 27 g of Aluminum

To calculate the amount, mass, and volume of chlorine required to react with 27 g of aluminum, we need to consider the balanced chemical equation for the reaction between aluminum and chlorine.

The balanced chemical equation for the reaction is:

2 Al + 3 Cl2 -> 2 AlCl3

According to the equation, 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride.

Now, let's calculate the amount, mass, and volume of chlorine required step by step:

Step 1: Calculate the Amount of Aluminum

Given that we have 27 g of aluminum, we need to calculate the amount of aluminum in moles.

The molar mass of aluminum (Al) is approximately 26.98 g/mol.

To calculate the amount of aluminum, we can use the formula:

Amount (in moles) = Mass (in grams) / Molar mass

Substituting the values, we have:

Amount of aluminum = 27 g / 26.98 g/mol = 1.001 moles

Step 2: Calculate the Amount of Chlorine

According to the balanced chemical equation, 2 moles of aluminum react with 3 moles of chlorine gas.

Using the mole ratio, we can calculate the amount of chlorine required.

Amount of chlorine = (Amount of aluminum / 2) * (3 moles of chlorine / 2 moles of aluminum)

Substituting the value, we have:

Amount of chlorine = (1.001 moles / 2) * (3 moles of chlorine / 2 moles of aluminum) = 1.502 moles

Step 3: Calculate the Mass of Chlorine

To calculate the mass of chlorine required, we need to multiply the amount of chlorine by its molar mass.

The molar mass of chlorine (Cl2) is approximately 70.91 g/mol.

Mass of chlorine = Amount of chlorine * Molar mass

Substituting the value, we have:

Mass of chlorine = 1.502 moles * 70.91 g/mol = 106.6 g

Step 4: Calculate the Volume of Chlorine at STP

To calculate the volume of chlorine at standard temperature and pressure (STP), we can use the ideal gas law.

The molar volume of an ideal gas at STP is approximately 22.4 L/mol.

Volume of chlorine = Amount of chlorine * Molar volume at STP

Substituting the value, we have:

Volume of chlorine = 1.502 moles * 22.4 L/mol = 33.7 L

Summary:

Therefore, to react with 27 g of aluminum, containing 20% impurities, we would need approximately: - Amount of chlorine: 1.502 moles - Mass of chlorine: 106.6 g - Volume of chlorine at STP: 33.7 L

Please note that these calculations assume ideal conditions and may vary slightly in practice due to factors such as impurities and deviations from ideal gas behavior.